论马蒂亚谢维奇定理与斯莫林斯基定理的关系

Agnieszka Peszek, A. Tyszka
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引用次数: 0

摘要

Yuri Matiyasevich的定理指出,所有具有非负整数解的丢梵图方程的集合是不递归的。克雷格·斯莫林斯基定理指出,所有非负整数的丢芬图方程的最多有有限个解的集合是不可递归枚举的。设R是Q的子函数,有或没有1。通过{H_10}(R),我们表示了是否存在一个算法的问题,该算法可以判定任意给定的整数系数的丢图图方程在R中是否有解。我们证明了{H_10}(R)的正解意味着所有在R中有有限个解的丢图图方程的集合是递归可枚举的。我们给出了无限集R \subseteq Q的逆蕴涵,使得存在可计算函数\tau _1, \tau _2:N \to Z满足(\forall N \in N \tau _2(N) \neq 0) \wedge ({\frac{\tau_1(n)}{\tau_2(n)}:N \in N}=R)。R=N的这个推论保证了Smorynski定理是由Matiyasevich定理推导出来的。哈维·弗里德曼(Harvey Friedman)推测,具有有理解的多个变量整数系数多项式的集合不是递归的。哈维·弗里德曼(Harvey Friedman)猜想,只有有限多个有理数解的整数系数若干变量多项式的集合不是递归可枚举的。这些猜想与R=Q时的结果是等价的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
On the Relationship Between Matiyasevich's and Smorynski's Theorems
Yuri Matiyasevich's theorem states that the set of all Diophantine equations which have a solution in non-negative integers is not recursive. Craig Smorynski's theorem states that the set of all Diophantine equations which have at most finitely many solutions in non-negative integers is not recursively enumerable. Let R be a subring of Q with or without 1. By H_{10}(R), we denote the problem of whether there exists an algorithm which for any given Diophantine equation with integer coefficients, can decide whether or not the equation has a solution in R. We prove that a positive solution to H_{10}(R) implies that the set of all Diophantine equations with a finite number of solutions in R is recursively enumerable. We show the converse implication for every infinite set R \subseteq Q such that there exist computable functions \tau_1,\tau_2:N \to Z which satisfy (\forall n \in N \tau_2(n) \neq 0) \wedge ({\frac{\tau_1(n)}{\tau_2(n)}: n \in N}=R). This implication for R=N guarantees that Smorynski's theorem follows from Matiyasevich's theorem. Harvey Friedman conjectures that the set of all polynomials of several variables with integer coefficients that have a rational solution is not recursive. Harvey Friedman conjectures that the set of all polynomials of several variables with integer coefficients that have only finitely many rational solutions is not recursively enumerable. These conjectures are equivalent by our results for R=Q.
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