发送带有未知噪声的消息

Abhinav Aggarwal, Varsha Dani, Thomas P. Hayes, Jared Saia
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引用次数: 5

摘要

Alice和Bob通过双向通道连接,Alice想向Bob发送L位的消息。对手在信道上翻转任意但有限的位T。这个对手知道我们的算法和Alice的消息,但不知道Alice或Bob生成的任何私有随机比特,也不知道通过通道发送的比特,除非这些比特可以通过Alice的消息或我们的算法来预测。我们希望Bob接收到Alice的消息,并让两个玩家终止,错误概率不超过δ > 0,其中δ是Alice和Bob都知道的参数。不幸的是,Alice和Bob事先都不知道T的值,Bob事先也不知道L的值。我们描述了一种算法来解决上述问题,同时发送预期的L + O(T + min(T + 1, L /log L) log (L /δ))位。一种特殊情况是当δ = O (1/LC)时,对于某个常数c。那么当T = O (L /log L)时,发送的期望比特数是L + O (L),当T = Ω(L)时,发送的期望比特数是L + O (T),这是渐近最优的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Sending a Message with Unknown Noise
Alice and Bob are connected via a two-way channel, and Alice wants to send a message of L bits to Bob. An adversary flips an arbitrary but finite number of bits, T, on the channel. This adversary knows our algorithm and Alice's message, but does not know any private random bits generated by Alice or Bob, nor the bits sent over the channel, except when these bits can be predicted by knowledge of Alice's message or our algorithm. We want Bob to receive Alice's message and for both players to terminate, with error probability at most δ > 0, where δ is a parameter known to both Alice and Bob. Unfortunately, the value T is unknown in advance to either Alice or Bob, and the value L is unknown in advance to Bob. We describe an algorithm to solve the above problem while sending an expected L + O(T + min(T + 1, L /log L) log (L /δ)) bits. A special case is when δ = O (1/LC), for some constant c. Then when T = o (L /log L), the expected number of bits sent is L + o(L), and when T = Ω(L), the expected number of bits sent is L + O (T), which is asymptotically optimal.
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