具有强稳健性的两个证明者一轮博弈

Subhash Khot, S. Safra
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引用次数: 25

摘要

我们证明了对于任何固定素数$q \geq 5$和常数$\zeta >, 0$,它是NP-hard区分两个证明一轮博弈的答案是$q^6$的值至少是$1-\zeta$还是最多$\frac{4}{q}$。结果是通过结合两种技术获得的:(i)基于线性函数的{\it点对子空间}检验的内PCP。睾丸进行傅里叶分析。(ii)外部/内部PCP组合依赖于某种{\it覆盖Hadamard代码属性的子}代码。这是将Hadamard代码的{\it码字测试}转换为{\it一致性测试}的一种新的黑盒方法,从而导致完整的PCP构造。作为一个应用,我们证明了除非NP具有拟多项式时间确定性算法,否则二次规划问题在因子$(\log n)^{1/6 - o(1)}$内是近似的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
A Two Prover One Round Game with Strong Soundness
We show that for any fixed prime $q \geq 5$ and constant $\zeta >, 0$, it is NP-hard to distinguish whether a two prove one round game with $q^6$ answers has value at least $1-\zeta$ or at most $\frac{4}{q}$. The result is obtained by combining two techniques: (i) An Inner PCP based on the {\it point versus subspace} test for linear functions. The testis analyzed Fourier analytically. (ii) The Outer/Inner PCP composition that relies on a certain {\it sub-code covering} property for Hadamard codes. This is a new and essentially black-box method to translate a {\it codeword test}for Hadamard codes to a {\it consistency test}, leading to a full PCP construction. As an application, we show that unless NP has quasi-polynomial time deterministic algorithms, the Quadratic Programming Problem is in approximable within factor $(\log n)^{1/6 - o(1)}$.
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