寻找字符串的反盖

Mai Alzamel, A. Conte, Shuhei Denzumi, R. Grossi, C. Iliopoulos, Kazuhiro Kurita, Kunihiro Wasa
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引用次数: 2

摘要

字符串x的k反盖是长度为k的x的两两不同因子的集合,使得x的每个符号都包含在这些因子的至少一个出现中。k-anticover的存在可以被看作是一种非冗余的概念,它在计算生物学中有应用,在那里它们与各种非调节机制相关联。本文讨论了寻找字符串x的k-反盖问题的复杂性,证明了当k≥3时,该决策问题在一般字符串上是np完全的。我们还证明了当k = 2时,这个问题有一个多项式时间解。对于无界k,我们提供了一个精确的指数算法来寻找长度为n的字符串的k-反盖(或确定不存在),它在O * (min{3n−k3, (k (k+1) 2) n k+1})时间内使用多项式空间运行。2012 ACM学科分类:计算数学→词的组合
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Finding the Anticover of a String
A k-anticover of a string x is a set of pairwise distinct factors of x of equal length k, such that every symbol of x is contained into an occurrence of at least one of those factors. The existence of a k-anticover can be seen as a notion of non-redundancy, which has application in computational biology, where they are associated with various non-regulatory mechanisms. In this paper we address the complexity of the problem of finding a k-anticover of a string x if it exists, showing that the decision problem is NP-complete on general strings for k ≥ 3. We also show that the problem admits a polynomial-time solution for k = 2. For unbounded k, we provide an exact exponential algorithm to find a k-anticover of a string of length n (or determine that none exists), which runs in O∗(min{3 n−k 3 , ( k(k+1) 2 ) n k+1 }) time using polynomial space. 2012 ACM Subject Classification Mathematics of computing → Combinatorics on words
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