二部有向图的Berges对偶猜想的证明

Caroline Aparecida de Paula Silva, C. N. D. Silva, Orlando Lee
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引用次数: 1

摘要

给定一个(顶点)着色C = c1, c2,…C m (P a有向图D)和一个正整数k,则C的k范数定义为C k = mi =1 min C i, k。如果着色C的k范数ck在所有着色中最小,则该着色C是k最优的。A(路径)k-pack P k是至多k个顶点不相交路径的集合。一个着色C和一个k包P k是正交的,如果每个颜色类在P k中与尽可能多的路径相交,也就是说,对于每个路径P j P k,如果ci k, ci P j = 1,否则ci的每个顶点都在P k的不同路径上。1982年,Berge推测,对于每一个k-最优着色C,存在一个k包P k正交于C。这个猜想对于任意有向图都是假的,有一个奇循环的反例。本文对二部有向图证明了这个猜想。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
A proof for Berges Dual Conjecture for Bipartite Digraphs
Given a (vertex)-coloring C = C 1 , C 2 , ...C m of P a digraph D and a positive integer k, the k-norm of C is defined as C k = m i=1 min C i, k. A coloring C is k-optimal if its k-norm C k is minimum over all colorings. A (path) k-pack P k is a collection of at most k vertex-disjoint paths. A coloring C and a k-pack P k are orthogonal if each color class intersects as many paths as possible in P k , that is, if C i k, C i P j = 1 for every path P j P k , otherwise each vertex of C i lies in a different path of P k . In 1982, Berge conjectured that for every k-optimal coloring C there is a k-pack P k orthogonal to C. This conjecture is false for arbitrary digraphs, having a counterexample with odd cycle. In this paper we prove this conjecture for bipartite digraphs.
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