提高小型光伏太阳能应用中自用份额的方法

A. Annuk, M. Hovi, Janar Kalder, T. Kabanen, R. Ilves, M. Märss, B. Martinkauppi, P. Miidla
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引用次数: 5

摘要

本文以某住宅为例,分析了提高光伏自用电量的可能性。这对于从光伏电站向微电网发电很重要;减少从电网购买的电量,也可以用光伏电站产生的电力取代部分消耗的电力。这篇文章使用了一个爱沙尼亚普通住宅的消费图表,它分别显示了热水和不可移动负荷(白色家电、照明、电视机等)的消费。光伏电站的生产曲线图是2.5 kW太阳能电站的实测产量与本案例的年消耗量的比例。为了增加太阳能电力在消费中的份额,已经使用了负载转移技术,将水和电池都部署为存储设备。光伏电站的生产和消费数据每隔5分钟平均记录一次。研究的目的是在锅炉和电池的不可移动负荷后,在剩余能量存储的情况下,找到热水箱和电池的最佳容量。在不可移动负载能量不足的情况下,如果有可用的电源,则由电池提供。按比例计算,光伏电站的能源产量为3472千瓦时/年,这是优化后的热水箱5千瓦时和电池3千瓦时能源容量的基础。在这些情况下,需求覆盖因子的值为0.657。如果没有存储设备,则为0.152。这些结果可扩展到更大或更小的解决方案。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Methods for Increasing Shares of Self-Consumption in Small PV Solar Energy Applications
The article analyses the possibilities of increasing PV electricity self-consumption, based on the data of a residential house. This is important for producing electricity from a PV station to the microgrid; to reduce the amount of electricity purchased from the grid, also to replace part of the electricity consumed with the electricity produced by the PV station. The article uses a previously measured consumption graph of an average Estonian residential house, which separately displays the consumption of hot water and non-shiftable load (white goods, lighting, TV set, etc.). The production graph of the PV station is the measured production of 2.5 kW solar station scaled to the annual consumption of this case. To increase the share of solar electricity in consumption, load shifting technology has been used, with both water and batteries deployed as storage devices. The PV station production and consumption data are recorded at 5-minute averaging intervals. The research aims to find the optimal capacity of the hot water tank and the battery, provided that the excess energy is stored after the non-shiftable load in both the boiler and the battery. In the case of a non-shiftable load energy deficit, it is provided from the battery, if there is a supply available. The energy production, scaled to equal the consumption, of the PV station was 3472 kWh / year, which was the basis for the energy capacity of 5 kWh for the optimized hot water tank and 3 kWh for the battery. In these conditions, the value of the demand cover factor is 0.657. Without storage devices, it would be 0.152. These results are scalable to bigger or smaller solutions.
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