{"title":"Polyominoes","authors":"S. Golomb, D. Klarner","doi":"10.1201/9781420035315.ch15","DOIUrl":null,"url":null,"abstract":"recurrence relation a n = 5 a n − 1 − 7 a n − 2 + 4 a n − 3 for n ≥ 5 with initial values a 1 = 1 , a 2 = 2 , a 3 = 6 , and a 4 = 19","PeriodicalId":156768,"journal":{"name":"Handbook of Discrete and Computational Geometry, 2nd Ed.","volume":"51 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"2020-06-30","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"131","resultStr":"{\"title\":\"Polyominoes\",\"authors\":\"S. Golomb, D. Klarner\",\"doi\":\"10.1201/9781420035315.ch15\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"recurrence relation a n = 5 a n − 1 − 7 a n − 2 + 4 a n − 3 for n ≥ 5 with initial values a 1 = 1 , a 2 = 2 , a 3 = 6 , and a 4 = 19\",\"PeriodicalId\":156768,\"journal\":{\"name\":\"Handbook of Discrete and Computational Geometry, 2nd Ed.\",\"volume\":\"51 1\",\"pages\":\"0\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"2020-06-30\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"131\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Handbook of Discrete and Computational Geometry, 2nd Ed.\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.1201/9781420035315.ch15\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Handbook of Discrete and Computational Geometry, 2nd Ed.","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1201/9781420035315.ch15","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 131
摘要
recurrence关系a n = 5 n−1−7 a n−2 + 4 (n−3 for n≥5和价值观名字的首字母a = 1, a = 2, 3 = 6,和a - 4 = 19