一个关于环的反拉姆齐数的简短证明

Noorya Yousifi
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引用次数: 1

摘要

Ramsey定理指出存在一个最小正整数R(R, s),使得R(R, s)个顶点上的完全图的每一个蓝红边着色都包含R个顶点上的蓝色团或s个顶点上的红色团。本文包含了环的反拉姆齐定理的一个简化证明。如果在H和H0之间有一条边e,它隶属于NEWc(v)中某个颜色的v∈H,那么我们可以通过添加边e并删除H中某个与e颜色相同的v的边来使H和H0连通,因此得到的图G ~具有一个阶≥2(k+1/2)的连通分量,这与每个连通分量的阶≤k−1相矛盾。由于每个分量都是哈密顿分量且阶≥k+1/ 2,为了避免彩虹Ck,通过与声明1相同的论证类型,我们必须有|c(H, H0)| = 1。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
A short proof of anti-Ramsey number for cycles
Ramsey's theorem states that there exists a least positive integer R(r, s) for which every blue-red edge colouring of the complete graph on R(r, s) vertices contains a blue clique on r vertices or a red clique on s vertices. This work contains a simplified proof of Anti-Ramsey theorem for cycles. If there is an edge e between H and H0, incident to, say, some v ∈ H of color from NEWc(v), then we can make H and H0 connected by adding the edge e and deleting some edge incident to v of the same color as e in H, so the resulting graph G˜ has a connected component of order ≥ 2( k+1/2 ), which contradicts that every connected component is of order ≤ k − 1. Since each component is Hamiltonian and of order ≥ k+1/ 2 , to avoid a rainbow Ck, by the same type of argument as in Claim 1, we must have that |c(H, H0 )| = 1.
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