{"title":"一个关于环的反拉姆齐数的简短证明","authors":"Noorya Yousifi","doi":"10.54660/.ijmrge.2021.2.3.108-109","DOIUrl":null,"url":null,"abstract":"Ramsey's theorem states that there exists a least positive integer R(r, s) for which every blue-red edge colouring of the complete graph on R(r, s) vertices contains a blue clique on r vertices or a red clique on s vertices. This work contains a simplified proof of Anti-Ramsey theorem for cycles. If there is an edge e between H and H0, incident to, say, some v ∈ H of color from NEWc(v), then we can make H and H0 connected by adding the edge e and deleting some edge incident to v of the same color as e in H, so the resulting graph G˜ has a connected component of order ≥ 2( k+1/2 ), which contradicts that every connected component is of order ≤ k − 1. Since each component is Hamiltonian and of order ≥ k+1/ 2 , to avoid a rainbow Ck, by the same type of argument as in Claim 1, we must have that |c(H, H0 )| = 1.","PeriodicalId":377083,"journal":{"name":"International Journal of Multidisciplinary Research and Growth Evaluation","volume":"201 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"1900-01-01","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"1","resultStr":"{\"title\":\"A short proof of anti-Ramsey number for cycles\",\"authors\":\"Noorya Yousifi\",\"doi\":\"10.54660/.ijmrge.2021.2.3.108-109\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"Ramsey's theorem states that there exists a least positive integer R(r, s) for which every blue-red edge colouring of the complete graph on R(r, s) vertices contains a blue clique on r vertices or a red clique on s vertices. This work contains a simplified proof of Anti-Ramsey theorem for cycles. If there is an edge e between H and H0, incident to, say, some v ∈ H of color from NEWc(v), then we can make H and H0 connected by adding the edge e and deleting some edge incident to v of the same color as e in H, so the resulting graph G˜ has a connected component of order ≥ 2( k+1/2 ), which contradicts that every connected component is of order ≤ k − 1. Since each component is Hamiltonian and of order ≥ k+1/ 2 , to avoid a rainbow Ck, by the same type of argument as in Claim 1, we must have that |c(H, H0 )| = 1.\",\"PeriodicalId\":377083,\"journal\":{\"name\":\"International Journal of Multidisciplinary Research and Growth Evaluation\",\"volume\":\"201 1\",\"pages\":\"0\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"1900-01-01\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"1\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"International Journal of Multidisciplinary Research and Growth Evaluation\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.54660/.ijmrge.2021.2.3.108-109\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"International Journal of Multidisciplinary Research and Growth Evaluation","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.54660/.ijmrge.2021.2.3.108-109","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
Ramsey's theorem states that there exists a least positive integer R(r, s) for which every blue-red edge colouring of the complete graph on R(r, s) vertices contains a blue clique on r vertices or a red clique on s vertices. This work contains a simplified proof of Anti-Ramsey theorem for cycles. If there is an edge e between H and H0, incident to, say, some v ∈ H of color from NEWc(v), then we can make H and H0 connected by adding the edge e and deleting some edge incident to v of the same color as e in H, so the resulting graph G˜ has a connected component of order ≥ 2( k+1/2 ), which contradicts that every connected component is of order ≤ k − 1. Since each component is Hamiltonian and of order ≥ k+1/ 2 , to avoid a rainbow Ck, by the same type of argument as in Claim 1, we must have that |c(H, H0 )| = 1.