{"title":"脚踏四面体","authors":"R. Robinson","doi":"10.1017/S0950184300002561","DOIUrl":null,"url":null,"abstract":"P 1 , = -o (rq — sp), p which gives the result required. Since my Solution 2 was, quite unintentionally, rather unfair to the method of partial derivatives, I feel that I ought to draw attention to this shorter solution. The fact that the above solution is merely shorter than the one which I gave does not however detract from the practical advantages of the differential method. Any experienced teacher knows that the step which presents real difficulty to the beginner is the obtaining of equation (1) above. Although in the case of the example which I happened to choose for illustration (and it may not have been the best for the purpose) the above solution by partial derivatives happens to be quite as short as the solution by differentials, the fact remains that, while the technique of differentiation, when once understood, is almost \" fool-proof,\" the pitfalls for the beginner in the solution given above are well known to every teacher of the subject. While the solution of a problem by partial derivatives may be quite a difficult piece of manipulation, exactly the same technique is required for the solution of a problem by differentials, however simple or complicated the problem in question may happen to be.","PeriodicalId":417997,"journal":{"name":"Edinburgh Mathematical Notes","volume":"17 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"1900-01-01","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"On pedal tetrahedra\",\"authors\":\"R. Robinson\",\"doi\":\"10.1017/S0950184300002561\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"P 1 , = -o (rq — sp), p which gives the result required. Since my Solution 2 was, quite unintentionally, rather unfair to the method of partial derivatives, I feel that I ought to draw attention to this shorter solution. The fact that the above solution is merely shorter than the one which I gave does not however detract from the practical advantages of the differential method. Any experienced teacher knows that the step which presents real difficulty to the beginner is the obtaining of equation (1) above. Although in the case of the example which I happened to choose for illustration (and it may not have been the best for the purpose) the above solution by partial derivatives happens to be quite as short as the solution by differentials, the fact remains that, while the technique of differentiation, when once understood, is almost \\\" fool-proof,\\\" the pitfalls for the beginner in the solution given above are well known to every teacher of the subject. While the solution of a problem by partial derivatives may be quite a difficult piece of manipulation, exactly the same technique is required for the solution of a problem by differentials, however simple or complicated the problem in question may happen to be.\",\"PeriodicalId\":417997,\"journal\":{\"name\":\"Edinburgh Mathematical Notes\",\"volume\":\"17 1\",\"pages\":\"0\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"1900-01-01\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Edinburgh Mathematical Notes\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.1017/S0950184300002561\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Edinburgh Mathematical Notes","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1017/S0950184300002561","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
摘要
P 1 = - 0 (rq - sp) P,它给出了所需的结果。由于我的解2,无意中,对偏导数法不公平,我觉得我应该把注意力集中在这个短解上。上面的解仅仅比我给出的解短,但这并不减损微分法的实际优点。任何有经验的老师都知道,对于初学者来说,真正困难的一步是得到上面的公式(1)。虽然在我碰巧选择的例子中(它可能不是最好的),上面的偏导数解恰好和微分解一样短,但事实是,虽然微分的技术一旦被理解,几乎是“万无一失”的,但上面给出的解决方案对于初学者来说的陷阱是每个老师都知道的。虽然用偏导数来解决问题可能是一个相当困难的操作,但用微分来解决问题也需要完全相同的技术,无论问题是简单还是复杂。
P 1 , = -o (rq — sp), p which gives the result required. Since my Solution 2 was, quite unintentionally, rather unfair to the method of partial derivatives, I feel that I ought to draw attention to this shorter solution. The fact that the above solution is merely shorter than the one which I gave does not however detract from the practical advantages of the differential method. Any experienced teacher knows that the step which presents real difficulty to the beginner is the obtaining of equation (1) above. Although in the case of the example which I happened to choose for illustration (and it may not have been the best for the purpose) the above solution by partial derivatives happens to be quite as short as the solution by differentials, the fact remains that, while the technique of differentiation, when once understood, is almost " fool-proof," the pitfalls for the beginner in the solution given above are well known to every teacher of the subject. While the solution of a problem by partial derivatives may be quite a difficult piece of manipulation, exactly the same technique is required for the solution of a problem by differentials, however simple or complicated the problem in question may happen to be.