关于无限有界对合格的同余的一个注记

C. Mureşan
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引用次数: 0

摘要

证明了一个无限(有界)对合格乃至伪kleene代数在2与它的元素数或等于它的子集数之间可以有任意数目的同余,而不管它的理想数与元素数相等还是理想数与子集相等。此外,当它们的同余数最多等于元素数时,可以选择这些对合格甚至伪kleene代数,使它们所有的格同余保留它们的对合数,从而使它们的格约化数与它们的同余数相同。在广义连续统假设下,这意味着一个无限(有界)对合格甚至伪kleene代数在2和它的子集之间可以有任意数量的同余,而不管它的理想个数是多少。因此,对于反正正交也成立,反正正交是一类准直模browwer - zadeh格。格的同余格的形状{下令代数问题,事实证明,只要刻画不是严格的数量比元素的数量,他们可以同构nonsingleton秩序井然的最大元素的集合的基数,提供最大的元素是严格join-irreducible有限格序代数和的情况下,对于antiortholattices至少有3个不同的元素,假设该良序集合的最大元素的前导也是严格连接不可约的;当然,在不改变所讨论的基数的情况下,可以对这些代数应用各种构造来获得具有不同结构的同余格。我们指出了类似结果在任意变化下成立的充分条件。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
A Note on Congruences of Infinite Bounded Involution Lattices
We prove that an infinite (bounded) involution lattice and even pseudo-Kleene algebra can have any number of congruences between 2 and its number of elements or equalling its number of subsets, regardless of whether it has as many ideals as elements or as many ideals as subsets. Furthermore, when they have at most as many congruences as elements, these involution lattices and even pseudo-Kleene algebras can be chosen such that all their lattice congruences preserve their involutions, so that they have as many congruences as their lattice reducts. Under the Generalized Continuum Hypothesis, this means that an infinite (bounded) involution lattice and even pseudo-Kleene algebra can have any number of congruences between 2 and its number of subsets, regardless of its number of ideals. Consequently, the same holds for antiortholattices, a class of paraorthomodular Brouwer-Zadeh lattices. Regarding the shapes of the congruence lattices of the lattice{ ordered algebras in question, it turns out that, as long as the number of congruences is not strictly larger than the number of elements, they can be isomorphic to any nonsingleton well-ordered set with a largest element of any of those cardinalities, provided its largest element is strictly join-irreducible in the case of bounded lattice-ordered algebras and, in the case of antiortholattices with at least 3 distinct elements, provided that the predecessor of the largest element of that well-ordered set is strictly join{irreducible, as well; of course, various constructions can be applied to these algebras to obtain congruence lattices with different structures without changing the cardinalities in question. We point out sufficient conditions for analogous results to hold in an arbitrary variety.
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