快速多匹配Lempel-Ziv

M. Pinho, W. Finamore, W. Pearlman
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引用次数: 8

摘要

只提供摘要形式。文献中最流行的编码器之一是LZ78,它是由Ziv和Lempel(1978)提出的。我们建立了一种递归的方法来找到最长的m元组匹配。我们证明了以下定理,该定理展示了如何从最长的m元组匹配中获得最长的(m+1)元组匹配。它表明(m+1)元组匹配是m元组匹配的第一个(m-1)个单词与下一个最长的双匹配的连接。因此,可以使用m元组匹配和计算最长双匹配的过程来找到最长(m+1)元组匹配。我们的定理如下。设A是一个源字母,设A*是A的所有有限字符串的集合,D/spl sub/A*,使得如果x/spl是in/D,则x的所有前缀都属于D。设u表示一个单侧无限序列。如果b/sub 1//sup m/是u中最长的m元组匹配,相对于D,则存在最长的(m+1)-元组匹配b/spl circ//sub 1//sup m+1/,使得b/spl circ//sub i/=b/sub i/,/spl forall/i/spl isin/{1,…m-1}。我们实现了快速mmLZ,结果显示在坎特伯雷语料库(Arnold and Bell, 1997)中,压缩比LZW提高了约5%,并且几乎没有额外的计算成本。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Fast multi-match Lempel-Ziv
Summary form only given. One of the most popular encoders in the literature is the LZ78, which was proposed by Ziv and Lempel (1978). We establish a recursive way to find the longest m-tuple match. We prove the following theorem that shows how to obtain a longest (m+1)-tuple match from the longest m-tuple match. It shows that a (m+1)-tuple match is the concatenation of the first (m-1) words of the m-tuple match with the next longest double match. Therefore, the longest (m+1)-tuple match can be found using the m-tuple match and a procedure to compute the longest double match. Our theorem is as follows. Let A be a source alphabet, let A* be the set of all finite strings of A, and D/spl sub/A*, such that if x/spl isin/D then all prefixes of x belong to D. Let u denote a one-sided infinite sequence. If b/sub 1//sup m/ is the longest m-tuple match in u, with respect to D, then there is a longest (m+1)-tuple match b/spl circ//sub 1//sup m+1/, such that b/spl circ//sub i/=b/sub i/,/spl forall/i/spl isin/{1,...m-1}. We implemented the fast mmLZ and the results show a improvement in compression of around 5% over the LZW, in the Canterbury Corpus (Arnold and Bell, 1997) with little extra computational cost.
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