{"title":"入口","authors":"E. Stevenson","doi":"10.1201/9780429337383-1","DOIUrl":null,"url":null,"abstract":"4. The number of moles of hydrogen molecules required to produce 20 moles of ammonia through Haber’s process is : (1) 10 (2) 20 (3) 30 (4) 40 (3) [NCERT XI-I-17] N2 + 3H2 2NH3 for 20 moles of NH3, 30 moles of H2 are required. 5. For an ideal solution, the correct option is : (1) mix S=0 at constant T and P (2) mix V 0 at constant T and P (3) mix H=0 at constant T and P (4) mix G=0 at constabnt T and P (3) [NCERT XI-I-45] For ideal solution S > 0, G < 0, H = 0 V = 0","PeriodicalId":185359,"journal":{"name":"The Grass Lark","volume":"27 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"2020-03-12","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"Entrance\",\"authors\":\"E. Stevenson\",\"doi\":\"10.1201/9780429337383-1\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"4. The number of moles of hydrogen molecules required to produce 20 moles of ammonia through Haber’s process is : (1) 10 (2) 20 (3) 30 (4) 40 (3) [NCERT XI-I-17] N2 + 3H2 2NH3 for 20 moles of NH3, 30 moles of H2 are required. 5. For an ideal solution, the correct option is : (1) mix S=0 at constant T and P (2) mix V 0 at constant T and P (3) mix H=0 at constant T and P (4) mix G=0 at constabnt T and P (3) [NCERT XI-I-45] For ideal solution S > 0, G < 0, H = 0 V = 0\",\"PeriodicalId\":185359,\"journal\":{\"name\":\"The Grass Lark\",\"volume\":\"27 1\",\"pages\":\"0\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"2020-03-12\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"The Grass Lark\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.1201/9780429337383-1\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"The Grass Lark","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1201/9780429337383-1","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
摘要
4. 5. 对于理想溶液,正确的选项是:(1)mix S=0 at T和P(2)mix V 0 at T和P(3)mix H=0 at T和P(4)mix G=0 at T和P (3) [NCERT xii - i -45]对于理想溶液S > 0,G < 0,H =0V =0
4. The number of moles of hydrogen molecules required to produce 20 moles of ammonia through Haber’s process is : (1) 10 (2) 20 (3) 30 (4) 40 (3) [NCERT XI-I-17] N2 + 3H2 2NH3 for 20 moles of NH3, 30 moles of H2 are required. 5. For an ideal solution, the correct option is : (1) mix S=0 at constant T and P (2) mix V 0 at constant T and P (3) mix H=0 at constant T and P (4) mix G=0 at constabnt T and P (3) [NCERT XI-I-45] For ideal solution S > 0, G < 0, H = 0 V = 0