钻头提取问题或t弹性函数

B. Chor, Oded Goldreich, J. Håstad, J. Friedman, S. Rudich, R. Smolensky
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引用次数: 384

摘要

我们考虑以下对抗情况。设n, m, t为任意整数,设f: {0,1}n→{0,1}m为函数。对手知道函数f,设置n个输入位的t,而其余的(n-t个输入,位)是随机选择的(独立且均匀概率分布)。对手试图阻止f的结果均匀分布在{0,1}m中。问题是,当被限制为f的输入位的t时,对手在n, m和t的什么值下必然无法使f的结果偏置:{0,1}n→{0,1}m。我们给出了m的各种下界和上界,允许肯定的答案。当t≤n/3和t≥2n/3时,这些边界比较接近。我们的研究结果在容错和密码学领域都有应用。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
The bit extraction problem or t-resilient functions
We consider the following adversarial situation. Let n, m and t be arbitrary integers, and let f : {0, 1}n → {0, 1}m be a function. An adversary, knowing the function f, sets t of the n input bits, while the rest (n-t input, bits) are chosen at random (independently and with uniform probability distribution) The adversary tries to prevent the outcome of f from being uniformly distributed in {0, 1}m. The question addressed is for what values of n, m and t does the adversary necessarily fail in biasing the outcome of f : {0,1}n → {0, 1}m, when being restricted to set t of the input bits of f. We present various lower and upper bounds on m's allowing an affirmative answer. These bounds are relatively close for t ≤ n/3 and for t ≥ 2n/3. Our results have applications in the fields of faulttolerance and cryptography.
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