分拣机器人在一个循环上的最小运动

Jae-Hoon Kim
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引用次数: 0

摘要

在具有个顶点的图形中,有一个唯一的方框最终放置在每个顶点上。因此,每个顶点和盒子都从1到编号,并且盒子应该放置在顶点上。但是,根据排列,盒子最初位于顶点上。在每一步中,机器人可以沿着视频的边缘行走,一次最多可以携带一个盒子。同样,当到达一个顶点时,机器人可以交换放置在那里的盒子和它携带的盒子。问题是最小化总步骤,使每个顶点都有自己的盒子,也就是说,洗牌后的盒子是排序的。在本文中,我们将找到最小步数的上界,并证明当视频为一个周期时,机器人的运动是在时间内找到的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Minimum Movement of a Robot for Sorting on a Cycle
In a graph   with  vertices, there is an unique box which is finally laid on each vertex. Thus each vertex and box is both numbered from 1 to  and the box  should be laid on the vertex  . But, the box  is initially located on the vertex  according to a permutation  . In each step, the robot can walk along an edge of  and can carry at most one box at a time. Also when arriving at a vertex, the robot can swap the box placed there with the box it is carrying. The problem is to minimize the total step so that every vertex has its own box, that is, the shuffled boxes are sorted. In this paper, we shall find an upper bound of the minimum number of steps and show that the movement of the robot is found in    time when  is a cycle.
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