常规语言和上下文无关语言的宽度

David Mestel
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引用次数: 3

摘要

给定一个偏序有限字母$\Sigma$和一种语言$L\subseteq \Sigma^*$, $L$中的反链可以有多大(其中$L$是给定字典顺序的)?更准确地说,由于$L$通常是无限的,我们应该问由长度$n$的词组成的最大反链的增长率。偏序的这一基本性质被称为宽度,在一篇合著的论文中,我们表明,计算一个确定性交互系统所允许的信息泄漏的问题可以简化为计算某种规则语言的宽度的问题。在本文中,我们证明了如果$L$是正则的,那么多项式反链增长与指数反链增长之间存在二分性。我们给出了一个多项式时间算法来区分这两种情况,并计算多项式增长的阶数,语言指定为NFA。对于上下文无关的语言,我们表明存在类似的二分法,但现在区分这两种情况的问题是无法确定的。最后,我们将字典顺序推广到树语言,并证明对于正则树语言存在多项式、指数和双指数反链增长之间的三分法。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Widths of Regular and Context-Free Languages
Given a partially-ordered finite alphabet $\Sigma$ and a language $L\subseteq \Sigma^*$, how large can an antichain in $L$ be (where $L$ is given the lexicographic ordering)? More precisely, since $L$ will in general be infinite, we should ask about the rate of growth of maximum antichains consisting of words of length $n$. This fundamental property of partial orders is known as the width, and in a companion work we show that the problem of computing the information leakage permitted by a deterministic interactive system modeled as a finite-state transducer can be reduced to the problem of computing the width of a certain regular language. In this paper, we show that if $L$ is regular then there is a dichotomy between polynomial and exponential antichain growth. We give a polynomial-time algorithm to distinguish the two cases, and to compute the order of polynomial growth, with the language specified as an NFA. For context-free languages we show that there is a similar dichotomy, but now the problem of distinguishing the two cases is undecidable. Finally, we generalise the lexicographic order to tree languages, and show that for regular tree languages there is a trichotomy between polynomial, exponential and doubly exponential antichain growth.
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