导航树与永久嘈杂的建议

Lucas Boczkowski, U. Feige, Amos Korman, Yoav Rodeh
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引用次数: 4

摘要

我们考虑一个树上的搜索问题,其中智能体从树的根部开始,目的是通过沿着边缘移动,同时依赖局部的部分信息来定位一个对抗性放置的宝藏。具体来说,树中的每个节点都持有一个指向其邻居的指针,称为通知。节点故障的概率为q。非故障节点的建议指向离宝藏更近的邻居,故障节点的建议指向一个均匀随机的邻居。至关重要的是,该建议是永久的,从某种意义上说,再次查询同一节点将产生相同的答案。设Δ表示最大度。对于期望的移动次数(边缘遍历),直到找到宝藏,我们表明,当噪声参数q大约为1√Δ时,会发生相变。在阈值以下,存在一种期望步数为O(D√Δ)的算法,其中D为宝藏的深度,而在阈值以上,每个搜索算法都有一个期望步数,它在D上是指数的,在节点数n上是多项式的。相反,如果我们要求以至少1−Δ的概率找到宝藏,则对于每一个固定的O,如果q < 1/Δ O,则存在一种概率为1−δ的搜索策略,通过(Δ−1D)O(1/ε)移动找到宝藏。此外,我们证明(Δ−1D)Ω(1/ε)移动是必要的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Navigating in Trees with Permanently Noisy Advice
We consider a search problem on trees in which an agent starts at the root of a tree and aims to locate an adversarially placed treasure, by moving along the edges, while relying on local, partial information. Specifically, each node in the tree holds a pointer to one of its neighbors, termed advice. A node is faulty with probability q. The advice at a non-faulty node points to the neighbor that is closer to the treasure, and the advice at a faulty node points to a uniformly random neighbor. Crucially, the advice is permanent, in the sense that querying the same node again would yield the same answer. Let Δ denote the maximum degree. For the expected number of moves (edge traversals) until finding the treasure, we show that a phase transition occurs when the noise parameter q is roughly 1 √Δ. Below the threshold, there exists an algorithm with expected number of moves O(D √Δ), where D is the depth of the treasure, whereas above the threshold, every search algorithm has an expected number of moves, which is both exponential in D and polynomial in the number of nodes n. In contrast, if we require to find the treasure with probability at least 1 − δ, then for every fixed ɛ > 0, if q < 1/Δɛ, then there exists a search strategy that with probability 1 − δ finds the treasure using (Δ −1D)O(1/ε) moves. Moreover, we show that (Δ −1D)Ω(1/ε) moves are necessary.
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