使用后缀数组对字符串进行非重叠计数

Kyoji Umemura, Yuto Kohara, Nudtawon Yusuk, Ayaka Takamoto, Mitsuo Yoshida
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引用次数: 1

摘要

“aaa”中的“aa”有两种计数方法。第一种方法是重叠计数,该方法在“aaa”中计数两个“aa”。重叠计数使用中间的“a”两次。另一种方法是非重叠计数,它只能计数“aaa”中的一个“aa”。非重叠计数使用每个字符一次;因此,“aaa”中只有一个“aa”。本文给出了由相关字符串的重叠计数计算字符串的非重叠计数的公式。由于后缀数组是一种有效的数据结构,为了得到任意字符串的重叠计数,我们可以利用本文给出的公式来得到给定字符串的非重叠计数。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Non-overlapping Counting of String Using Suffix Array
There are two counting methods of "aa" in "aaa". The first method is overlapping count and this method count two "aa" in "aaa". The overlapping count uses the middle "a" twice. The other method is non-overlapping count which can count only one "aa" in "aaa". Non-overlapping counting uses each character once; therefore, there is only one "aa" in "aaa". In this paper, we provide the formulas to compute non-overlapping count of a string from the overlapping count of the related strings. Because a suffix array is known to be an efficient data structure, to obtain overlapping count of any string we can use suffix array to obtain the non-overlapping count of the given string by the formula which is presented in this paper.
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