在递归序列(n + !) = x (n-14) / (1 + x (n - 2) x(存在)x (n-8) x (n - 11)]

MANAS Journal of Engineering Pub Date : 2020-12-21 DOI:10.51354/mjen.748450

B. Oğul, D. Şi̇mşek

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引用次数: 2

摘要

本文给出了初始条件为正实数的差分方程x(n+!) = x(n-14) / [1 + x(n-2) x(n-5) x(n-8) x(n-11)]的解。方程的初始条件是任意正实数。我们研究了这个方程的周期性质。并给出了数值算例和解图。

本文章由计算机程序翻译，如有差异，请以英文原文为准。

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On the Recursive Sequence x(n+!) = x(n-14) / [1 + x(n-2) x(n-5) x(n-8) x(n-11)]

In this paper, given solutions fort he following difference equation x(n+!) = x(n-14) / [1 + x(n-2) x(n-5) x(n-8) x(n-11)] where the initial conditions are positive real numbers. The initial conditions of the equation are arbitrary positive real numbers. We investigate periodic behavior of this equation. Also some numerical examples and graphs of solutions are given.

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MANAS Journal of Engineering

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