鹤滩猜想

D. M. Barrington, N. Immerman, C. Lautemann, Nicole Schweikardt, D. Thérien
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引用次数: 15

摘要

如果在字母表A上的语言L中有一个字母e/spl /A,使得在A*中的任何单词中插入或删除e都不会改变它在L中的隶属性(或非隶属性),那么我们就说它有一个中性字母。我们推测,它使除次序谓词以外的所有数值谓词都变得无用,即,如果具有中性字母的语言L在线性次序的一阶逻辑中是不可定义的,那么它在一阶逻辑中是不可定义的。具有任意一组/spl Nscr/数值谓词的逻辑。我们详细地研究了这个猜想,表明对于/spl Nscr/={+, *},它已经失效,或者对于任何允许计数到m次迭代对数的集合/spl Nscr/可能更强,对于任何常数m。在积极的方面,我们证明了所有一元数值谓词的猜想,对于/spl Nscr/={+},对于一阶逻辑的片段BC(/spl Sigma/),对于二进制字母。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
The Crane Beach Conjecture
A language L over an alphabet A is said to have a neutral letter if there is a letter e/spl isin/A such that inserting or deleting e's from any word in A* does not change its membership (or non-membership) in L. The presence of a neutral letter affects the definability of a language in first-order logic. It was conjectured that it renders all numerical predicates apart from the order predicate useless, i.e., that if a language L with a neutral letter is not definable in first-order logic with linear order then it is not definable in first-order. Logic with any set /spl Nscr/ of numerical predicates. We investigate this conjecture in detail, showing that it fails already for /spl Nscr/={+, *}, or possibly stronger for any set /spl Nscr/ that allows counting up to the m times iterated logarithm, 1g/sup (m)/, for any constant m. On the positive side, we prove the conjecture for the case of all monadic numerical predicates, for /spl Nscr/={+}, for the fragment BC(/spl Sigma/) of first-order logic, and for binary alphabets.
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