到底是哪个十字路口的号码?(计算几何)

J. Pach, G. Tóth
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引用次数: 1

摘要

图G的绘制是一种映射,它将平面的每个顶点分配一个点,并将连接相应两点的简单连续弧线分配给每个边。G的交叉点数是任意G图中交叉点的最小个数,我们定义两个新参数如下:两两交叉数(如:G的奇相交数是相交的边对的最小数目。我们证明了这些参数的每一个的确定都是一个np完全问题。我们还证明了这些数中最大的数(交叉数)不能超过最小的数(奇数交叉数)的平方的两倍。我们的证明是基于Hanani的一个旧结果的推广,这是一个独立的兴趣。设G是一个图,设E/下标0/是它的边的一个子集,使得有一个G的图,其中每条属于E/下标0/的边与任何其他边相交偶数次。然后可以重新绘制G,使E/sub 0/的元素不涉及任何交叉。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Which crossing number is it, anyway? [computational geometry]
A drawing of a graph G is a mapping which assigns to each vertex a point of the plane and to each edge a simple continuous arc connecting the corresponding two points. The crossing number of G is the minimum number of crossing points in any drawing of G. We define two new parameters, as follows. The pairwise crossing number (resp. the odd-crossing number) of G is the minimum number of pairs of edges that cross (resp. cross an odd number of times) over all drawings of G. We prove that the determination of each of these parameters is an NP-complete problem. We also prove that the largest of these numbers (the crossing number) cannot exceed twice the square of the smallest (the odd-crossing number). Our proof is based on the following generalization of an old result of Hanani, which is of independent interest. Let G be a graph and let E/sub 0/ be a subset of its edges such that there is a drawing of G, in which every edge belonging E/sub 0/ crosses any other edge an even number of times. Then G can be redrawn so that the element of E/sub 0/ are not involved in any crossing.
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