四分位数的等和(在里士满方程中)(ax4+by4+cz4+dw4=0)

S. Tomita, Oliver Couto
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引用次数: 0

摘要

考虑下面提到的等式:ax4+by4+cz4+dw4=0—[1]。在第(1)节中,我们考虑方程[1]的系数条件下的解。即乘积(abcd)=平方。在第[2]节中,我们考虑方程[1]的系数,其中系数的乘积(abcd)不等于平方。历史上,Ajai Choudhry, A. Bremner, M.Ulas [ref 5]在2014年研究了方程[1]。里士满[参考文献1和2]也在1944年和1948年做了一些基础工作。本文更进一步,利用唯一恒等式找到了许多参数解和新的小数值解。恒等式是唯一的,因为它们是混合幂(四次和二次变量的组合),然后转换为只有四次恒等式。作为部分[B]的额外奖励,我们通过椭圆平均值提出了(n < 50)的几个四次(4-1-n)数值解。本文还给出了计算机蛮力搜索得到的(4-1-n)方程的数值解表[ref # 7]。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Equal Sums of Quartics (In Context with the Richmond Equation) (ax4+by4+cz4+dw4=0)
Consider the below mentioned Equation: ax4+by4+cz4+dw4=0---[1]. In section (1) we consider solution's with the condition on the coefficient's of equation[1]. Namely the product (abcd)=square. In section [2] we consider the coefficients of Equation [1], with the product of coefficient's (abcd) not equal to a square. Historically Equation [1] has been studied by Ajai Choudhry, A. Bremner, M.Ulas [ref. 5] in 2014. Also Richmond [ref. 1 & 2] has done some ground work in 1944 & 1948. This paper has gone a step further, by finding many parametric solutions & new small numerical solutions by the use of unique Identities. The identities are unique, because they are of mixed powers (combination of quartic & quadratic variables) which are then converted to only degree four identities. As an added bonus in section [B], we came up with a few quartic (4-1-n ) numerical solutions for (n < 50) by elliptical mean's. A table of numerical solutions for the (4-1-n) Equation arrived at by brute force computer search is also given [ref # 7].
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