Rb与H2、CH4和C2H6碰撞时激发态的失活和反应

SPIE LASE Pub Date : 2016-04-22 DOI:10.1117/12.2218119
V. Azyazov, A. P. Torbin, A. Mebel, S. Bresler, M. Heaven
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引用次数: 1

摘要

碱蒸汽激光器通常使用甲烷(CH4)或乙烷(C2H6)来诱导光泵浦能级(n2P3/2)和上层激光能级(n2P1/2)之间的能量转移。一个复杂的问题是,碱金属最终会与碳氢化合物发生反应。对于通过能量池过程激发的碱原子,如Rb(5p)+Rb(5p)→Rb(*)+Rb(5s),反应变成放热的,其中*表示6s, 6p或4d。我们用激光泵浦探针方法研究了Rb(n2P)与CH4和C2H6在n=6和7状态下的反应。泵探针测量表明Rb的损失是由于一个反应。令人惊讶的是,RbH产物没有被CH4和C2H6检测到。用高阶从头计算方法研究了Rb、甲烷和乙烷之间的反应相互作用。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Deactivation and reaction of excited states of Rb in collisions with H2, CH4 and C2H6
Alkali vapor lasers commonly use methane (CH4) or ethane (C2H6) to induce energy transfer between the optically pumped level (n2P3/2) and the upper laser level (n2P1/2). A complication is that the alkali metal eventually reacts with the hydrocarbons. The reaction becomes exothermic for alkali atoms that have been excited by energy pooling processes such as Rb(5p)+Rb(5p)→Rb(*)+Rb(5s), where * indicates 6s, 6p or 4d. We have used laser pump-probe methods to examine the reactions of Rb(n2P) with CH4, and C2H6 for states with n=6 and 7. Pump-probe measurements indicated a loss of Rb due to a reaction. Surprisingly, the RbH product was not detected with CH4, and C2H6. High-level ab initio calculations have been used to study the reactive interactions between Rb, methane and ethane.
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