Feasibly constructive proofs and the propositional calculus (Preliminary Version)

S. Cook
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引用次数: 227

Abstract

The motivation for this work comes from two general sources. The first source is the basic open question in complexity theory of whether P equals NP (see [1] and [2]). Our approach is to try to show they are not equal, by trying to show that the set of tautologies is not in NP (of course its complement is in NP). This is equivalent to showing that no proof system (in the general sense defined in [3]) for the tautologies is “super” in the sense that there is a short proof for every tautology. Extended resolution is an example of a powerful proof system for tautologies that can simulate most standard proof systems (see [3]). The Main Theorem (5.5) in this paper describes the power of extended resolution in a way that may provide a handle for showing it is not super. The second motivation comes from constructive mathematics. A constructive proof of, say, a statement @@@@×A must provide an effective means of finding a proof of A for each value of x, but nothing is said about how long this proof is as a function of x. If the function is exponential or super exponential, then for short values of x the length of the proof of the instance of A may exceed the number of electrons in the universe. In section 2, I introduce the system PV for number theory, and it is this system which I suggest properly formalizes the notion of a feasibly constructive proof.
可行构造证明与命题演算(初版)
这项工作的动机一般来自两个来源。第一个来源是复杂性理论中关于P是否等于NP的基本开放问题(参见[1]和[2])。我们的方法是试图证明它们是不相等的,通过试图证明重言式集合不是NP(当然它的补是NP)这相当于表明,对于重言式,没有一个证明系统(在[3]中定义的一般意义上)是“超级”的,因为每个重言式都有一个简短的证明。扩展分辨率是一个强大的重言式证明系统的例子,它可以模拟大多数标准证明系统(参见[3])。本文中的主要定理(5.5)描述了扩展分辨率的力量,它可以提供一个句柄来表明它不是超级的。第二个动机来自构造数学。例如,一个命题@@@@×A的建设性证明必须提供一种有效的方法来找到每个x值的A的证明,但没有说这个证明作为x的函数有多长。如果函数是指数或超指数的,那么对于x的短值,A实例的证明的长度可能超过宇宙中电子的数量。在第2节中,我介绍了数论的PV系统,我认为正是这个系统正确地形式化了可行构造证明的概念。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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