On Hardy type inequalities for weighted quasideviation means

Zsolt P'ales, P. Pasteczka
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引用次数: 5

Abstract

Using recent results concerning the homogenization and the Hardy property of weighted means, we establish sharp Hardy constants for concave and monotone weighted quasideviation means and for a few particular subclasses of this broad family. More precisely, for a mean $\mathscr{D}$ like above and a sequence $(\lambda_n)$ of positive weights such that $\lambda_n/(\lambda_1+\dots+\lambda_n)$ is nondecreasing, we determine the smallest number $H \in (1,+\infty]$ such that $$ \sum_{n=1}^\infty \lambda_n \mathscr{D}\big((x_1,\dots,x_n),(\lambda_1,\dots,\lambda_n)\big) \le H \cdot \sum_{n=1}^\infty \lambda_n x_n \text{ for all }x \in \ell_1(\lambda). $$ It turns out that $H$ depends only on the limit of the sequence $(\lambda_n/(\lambda_1+\dots+\lambda_n))$ and the behaviour of the mean $\mathscr{D}$ near zero.
关于加权拟对称均值的Hardy型不等式
利用最近关于加权均值的齐次化和Hardy性质的结果,我们建立了凹拟合均值和单调拟合均值的尖锐Hardy常数,以及这个大族的几个特殊子类。更准确地说,对于像上面这样的平均值$\mathscr{D}$和一个正权重的序列$(\lambda_n)$,使得$\lambda_n/(\lambda_1+\dots+\lambda_n)$是非递减的,我们确定最小的数$H \in (1,+\infty]$,使得$$ \sum_{n=1}^\infty \lambda_n \mathscr{D}\big((x_1,\dots,x_n),(\lambda_1,\dots,\lambda_n)\big) \le H \cdot \sum_{n=1}^\infty \lambda_n x_n \text{ for all }x \in \ell_1(\lambda). $$事实证明,$H$仅取决于序列$(\lambda_n/(\lambda_1+\dots+\lambda_n))$的极限和平均值$\mathscr{D}$接近零的行为。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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