Minimal Total Weighted Tardiness in Tight-Tardy Single Machine Preemptive Idling-Free Scheduling

IF 0.5 Q4 COMPUTER SCIENCE, THEORY & METHODS
V. Romanuke
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引用次数: 11

Abstract

Abstract Two possibilities of obtaining the minimal total weighted tardiness in tight-tardy single machine preemptive idling-free scheduling are studied. The Boolean linear programming model, which allows obtaining the exactly minimal tardiness, becomes too time-consuming as either the number of jobs or numbers of job parts increase. Therefore, a heuristic based on remaining available and processing periods is used instead. The heuristic schedules 2 jobs always with the minimal tardiness. In scheduling 3 to 7 jobs, the risk of missing the minimal tardiness is just 1.5 % to 3.2 %. It is expected that scheduling 12 and more jobs has at the most the same risk or even lower. In scheduling 10 jobs without a timeout, the heuristic is almost 1 million times faster than the exact model. The exact model is still applicable for scheduling 3 to 5 jobs, where the averaged computation time varies from 0.1 s to 1.02 s. However, the maximal computation time for 6 jobs is close to 1 minute. Further increment of jobs may delay obtaining the minimal tardiness at least for a few minutes, but 7 jobs still can be scheduled at worst for 7 minutes. When scheduling 8 jobs and more, the exact model should be substituted with the heuristic.
紧延迟单机抢占无空闲调度的最小总加权延迟
摘要研究了紧延迟单机抢占无空闲调度中总加权延迟最小的两种可能。布尔线性规划模型允许获得精确的最小延迟,但随着作业数量或作业部件数量的增加,该模型变得过于耗时。因此,使用基于剩余可用性和处理周期的启发式方法。启发式调度总是以最小的延迟调度2个作业。在调度3到7个作业时,错过最小延迟的风险仅为1.5%到3.2%。预计调度12个或更多的作业的风险最多是相同的,甚至更低。在没有超时的情况下调度10个作业时,启发式算法几乎比精确模型快100万倍。精确的模型仍然适用于调度3到5个作业,其中平均计算时间从0.1秒到1.02秒不等。然而,6个作业的最大计算时间接近1分钟。作业的进一步增加可能会延迟获得最小延迟至少几分钟,但7个作业仍然可以调度在最坏的7分钟。当调度8个或更多的作业时,应该用启发式模型代替精确模型。
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来源期刊
Applied Computer Systems
Applied Computer Systems COMPUTER SCIENCE, THEORY & METHODS-
自引率
10.00%
发文量
9
审稿时长
30 weeks
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