Bonds Intersecting Long Paths in \(k\) -Connected Graphs

Qing-Qing Zhao, B. Wei, Haidong Wu
{"title":"Bonds Intersecting Long Paths in \\(k\\) -Connected Graphs","authors":"Qing-Qing Zhao, B. Wei, Haidong Wu","doi":"10.1137/22m1481105","DOIUrl":null,"url":null,"abstract":"A well-known question of Gallai (1966) asked whether there is a vertex which passes through all longest paths of a connected graph. Although this has been verified for some special classes of graphs such as outerplanar graphs, circular arc graphs, and series-parallel graphs, the answer is negative for general graphs. In this paper, we prove among other results that if we replace the vertex by a bond, then the answer is affirmative. A bond of a graph is a minimal nonempty edge-cut. In particular, in any 2-connected graph, the set of all edges incident to a vertex is a bond, called a vertex-bond. Clearly, for a 2-connected graph, a path passes through a vertex $v$ if and only if it meets the vertex-bond with respect to $v$. Therefore, a very natural approach to Gallai's question is to study whether there is a bond meeting all longest paths. Let $p$ denote the length of a longest path of connected graphs. We show that for any 2-connected graph, there is a bond meeting all paths of length at least $p-1$. We then prove that for any 3-connected graph, there is a bond meeting all paths of length at least $p-2$. For a $k$-connected graph $(k\\ge3)$, we show that there is a bond meeting all paths of length at least $p-t+1$, where $t=\\Big\\lfloor\\sqrt{\\frac{k-2}{2}}\\Big\\rfloor$ if $p$ is even and $t=\\Big\\lceil\\sqrt{\\frac{k-2}{2}}\\Big\\rceil$ if $p$ is odd. Our results provide analogs of the corresponding results of P. Wu and S. McGuinness [Bonds intersecting cycles in a graph, Combinatorica 25 (4) (2005), 439-450] also.","PeriodicalId":21749,"journal":{"name":"SIAM J. Discret. Math.","volume":null,"pages":null},"PeriodicalIF":0.0000,"publicationDate":"2022-01-27","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"1","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"SIAM J. Discret. Math.","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1137/22m1481105","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 1

Abstract

A well-known question of Gallai (1966) asked whether there is a vertex which passes through all longest paths of a connected graph. Although this has been verified for some special classes of graphs such as outerplanar graphs, circular arc graphs, and series-parallel graphs, the answer is negative for general graphs. In this paper, we prove among other results that if we replace the vertex by a bond, then the answer is affirmative. A bond of a graph is a minimal nonempty edge-cut. In particular, in any 2-connected graph, the set of all edges incident to a vertex is a bond, called a vertex-bond. Clearly, for a 2-connected graph, a path passes through a vertex $v$ if and only if it meets the vertex-bond with respect to $v$. Therefore, a very natural approach to Gallai's question is to study whether there is a bond meeting all longest paths. Let $p$ denote the length of a longest path of connected graphs. We show that for any 2-connected graph, there is a bond meeting all paths of length at least $p-1$. We then prove that for any 3-connected graph, there is a bond meeting all paths of length at least $p-2$. For a $k$-connected graph $(k\ge3)$, we show that there is a bond meeting all paths of length at least $p-t+1$, where $t=\Big\lfloor\sqrt{\frac{k-2}{2}}\Big\rfloor$ if $p$ is even and $t=\Big\lceil\sqrt{\frac{k-2}{2}}\Big\rceil$ if $p$ is odd. Our results provide analogs of the corresponding results of P. Wu and S. McGuinness [Bonds intersecting cycles in a graph, Combinatorica 25 (4) (2005), 439-450] also.
相交于\(k\) -连通图中的长路径的键
Gallai(1966)提出了一个著名的问题,即是否存在一个顶点通过连通图的所有最长路径。虽然这已经在一些特殊类型的图中得到了验证,如外平面图、圆弧图和串并联图,但对于一般图,答案是否定的。在其他结果中,我们证明了如果用键代替顶点,那么答案是肯定的。图的键是最小的非空边切。特别地,在任何2连通图中,与一个顶点相关的所有边的集合是一个键,称为顶点键。显然,对于一个2连通图,一条路径经过顶点$v$当且仅当它满足关于$v$的顶点键。因此,对于Gallai的问题,一个非常自然的方法是研究是否存在所有最长路径的债券。设$p$表示连通图的最长路径的长度。我们证明了对于任何2连通图,存在一个键满足长度至少为$p-1$的所有路径。然后我们证明了对于任意3连通图,存在一个键满足长度至少为$p-2$的所有路径。对于一个$k$连通图$(k\ge3)$,我们证明存在一个键满足长度至少为$p-t+1$的所有路径,其中$t=\Big\lfloor\sqrt{\frac{k-2}{2}}\Big\rfloor$如果$p$是偶数,$t=\Big\lceil\sqrt{\frac{k-2}{2}}\Big\rceil$如果$p$是奇数。我们的结果也提供了P. Wu和S. McGuinness[图中的键相交环,Combinatorica 25(4)(2005), 439-450]的相应结果的类似物。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
求助全文
约1分钟内获得全文 求助全文
来源期刊
自引率
0.00%
发文量
0
×
引用
GB/T 7714-2015
复制
MLA
复制
APA
复制
导出至
BibTeX EndNote RefMan NoteFirst NoteExpress
×
提示
您的信息不完整,为了账户安全,请先补充。
现在去补充
×
提示
您因"违规操作"
具体请查看互助需知
我知道了
×
提示
确定
请完成安全验证×
copy
已复制链接
快去分享给好友吧!
我知道了
右上角分享
点击右上角分享
0
联系我们:info@booksci.cn Book学术提供免费学术资源搜索服务,方便国内外学者检索中英文文献。致力于提供最便捷和优质的服务体验。 Copyright © 2023 布克学术 All rights reserved.
京ICP备2023020795号-1
ghs 京公网安备 11010802042870号
Book学术文献互助
Book学术文献互助群
群 号:481959085
Book学术官方微信