{"title":"A curiosity About (−1)[e] +(−1)[2e] + ··· +(−1)[Ne]","authors":"F. Amoroso, M. Omarjee","doi":"10.2478/udt-2020-0007","DOIUrl":null,"url":null,"abstract":"Abstract Let α be an irrational real number; the behaviour of the sum SN (α):= (−1)[α] +(−1)[2α] + ··· +(−1)[Nα] depends on the continued fraction expansion of α/2. Since the continued fraction expansion of 2/2 \\sqrt 2 /2 has bounded partial quotients, SN(2)=O(log(N)) {S_N}\\left( {\\sqrt 2 } \\right) = O\\left( {\\log \\left( N \\right)} \\right) and this bound is best possible. The partial quotients of the continued fraction expansion of e grow slowly and thus SN(2e)=O(log(N)2log log(N)2) {S_N}\\left( {2e} \\right) = O\\left( {{{\\log {{\\left( N \\right)}^2}} \\over {\\log \\,\\log {{\\left( N \\right)}^2}}}} \\right) , again best possible. The partial quotients of the continued fraction expansion of e/2 behave similarly as those of e. Surprisingly enough SN(e)=O(log(N)log log(N)) 1188 .","PeriodicalId":23390,"journal":{"name":"Uniform distribution theory","volume":"70 1","pages":"1 - 8"},"PeriodicalIF":0.0000,"publicationDate":"2020-12-01","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"Uniform distribution theory","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.2478/udt-2020-0007","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
Abstract
Abstract Let α be an irrational real number; the behaviour of the sum SN (α):= (−1)[α] +(−1)[2α] + ··· +(−1)[Nα] depends on the continued fraction expansion of α/2. Since the continued fraction expansion of 2/2 \sqrt 2 /2 has bounded partial quotients, SN(2)=O(log(N)) {S_N}\left( {\sqrt 2 } \right) = O\left( {\log \left( N \right)} \right) and this bound is best possible. The partial quotients of the continued fraction expansion of e grow slowly and thus SN(2e)=O(log(N)2log log(N)2) {S_N}\left( {2e} \right) = O\left( {{{\log {{\left( N \right)}^2}} \over {\log \,\log {{\left( N \right)}^2}}}} \right) , again best possible. The partial quotients of the continued fraction expansion of e/2 behave similarly as those of e. Surprisingly enough SN(e)=O(log(N)log log(N)) 1188 .