ON A RESULT CONCERNING ALGEBRAIC CURVES PASSING THROUGH $n$-INDEPENDENT NODES

H. Hakopian
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引用次数: 1

Abstract

Let a set of nodes $\mathcal X$ in the plane be $n$-independent, i.e. each node has a fundamental polynomial of degree $n.$ Assume that $\#\mathcal X=d(n,n-3)+3= (n+1)+n+\cdots+5+3.$ In this paper we prove that there are at most three linearly independent curves of degree less than or equal to $n-1$ that pass through all the nodes of $\mathcal X.$ We provide a characterization of the case when there are exactly three such curves. Namely, we prove that then the set $\mathcal X$ has a very special construction: either all its nodes belong to a curve of degree $n-2,$ or all its nodes but three belong to a (maximal) curve of degree $n-3.$ This result complements a result established recently by H. Kloyan, D. Voskanyan, and H. Hakopian. Note that the proofs of the two results are completely different.
关于通过n个独立节点的代数曲线的一个结果
设平面上的一组节点$\mathcal X$是$n$独立的,即每个节点有一个阶为$n的基本多项式。假设美元\ # \ mathcal X = d (n, n - 3) + 3 = (n + 1) + n + \ cdots + 5 + 3。本文证明了至多有三条小于或等于n-1次的线性无关曲线通过数学x的所有节点,并给出了恰好有三条这样的曲线的一个刻画。也就是说,我们证明了集合$\mathcal X$有一个非常特殊的构造:它的所有节点都属于$n-2次曲线,$或者它的所有节点都属于$n-3次(最大)曲线。这一结果补充了最近由H. Kloyan, D. Voskanyan和H. Hakopian建立的结果。注意,这两个结果的证明是完全不同的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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