Towards a proof of the 2-to-1 games conjecture?

Irit Dinur, Subhash Khot, Guy Kindler, Dor Minzer, S. Safra
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引用次数: 75

Abstract

We present a polynomial time reduction from gap-3LIN to label cover with 2-to-1 constraints. In the “yes” case the fraction of satisfied constraints is at least 1 −ε, and in the “no” case we show that this fraction is at most ε, assuming a certain (new) combinatorial hypothesis on the Grassmann graph. In other words, we describe a combinatorial hypothesis that implies the 2-to-1 conjecture with imperfect completeness. The companion submitted paper [Dinur, Khot, Kindler, Minzer and Safra, STOC 2018] makes some progress towards proving this hypothesis. Our work builds on earlier work by a subset of the authors [Khot, Minzer and Safra, STOC 2017] where a slightly different hypothesis was used to obtain hardness of approximating vertex cover to within factor of √2−ε. The most important implication of this work is (assuming the hypothesis) an NP-hardness gap of 1/2−ε vs. ε for unique games. In addition, we derive optimal NP-hardness for approximating the max-cut-gain problem, NP-hardness of coloring an almost 4-colorable graph with any constant number of colors, and the same √2−ε NP-hardness for approximate vertex cover that was already obtained based on a slightly different hypothesis. Recent progress towards proving our hypothesis [Barak, Kothari and Steurer, ECCC TR18-077], [Dinur, Khot, Kindler, Minzer and Safra, STOC 2018] directly implies some new unconditional NP-hardness results. These include new points of NP-hardness for unique games and for 2-to-1 and 2-to-2 games. More recently, the full version of our hypothesis was proven [Khot, Minzer and Safra, ECCC TR18-006].
为了证明2比1博弈猜想?
我们提出了从gap-3LIN到具有2对1约束的标签覆盖的多项式时间缩减。在“是”的情况下,满足约束的分数至少是1−ε,而在“否”的情况下,我们证明这个分数最多是ε,假设在Grassmann图上的某个(新的)组合假设。换句话说,我们描述了一个包含不完全完备性2比1猜想的组合假设。同行提交的论文[Dinur, Khot, Kindler, Minzer和Safra, STOC 2018]在证明这一假设方面取得了一些进展。我们的工作建立在作者子集的早期工作的基础上[Khot, Minzer和Safra, STOC 2017],其中使用了一个略有不同的假设来获得近似顶点覆盖的硬度在√2−ε因子内。这项工作最重要的含义是(假设假设)np -硬度差距为1/2−ε与ε对于唯一游戏。此外,我们还推导出了逼近最大切割增益问题的最优np -硬度,具有任意常数颜色的几乎4色图着色的np -硬度,以及基于稍微不同的假设已经获得的近似顶点覆盖的相同√2−ε np -硬度。最近证明我们假设的进展[Barak, Kothari和Steurer, ECCC TR18-077], [Dinur, Khot, Kindler, Minzer和Safra, STOC 2018]直接暗示了一些新的无条件np -硬度结果。这包括针对独特游戏以及2对1和2对2游戏的新np硬度点。最近,我们的假设的完整版本被证明[Khot, Minzer和Safra, ECCC TR18-006]。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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