Relative exponential sum-symmetry model and orthogonal decomposition of the sum-symmetry model for ordinal square contingency tables

S. Ando
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引用次数: 0

Abstract

Summary This study proposes a new exponential sum-symmetry model for square contingency tables with same row and column ordinal classifications. In the existing exponential sum-symmetry (ESS) model, the probability that the sum of row and column levels is t, where the row level is less than the column level, is ∆t−2 times higher than the probability that the sum of row and column levels is t, where the row level is greater than the column level. On the other hand, in the proposed ESS model, the ratio of these two probabilities is ∆t/3. In other words, in the existing ESS model, the ratio of the two probabilities varies exponentially depending on the absolute gap between t and 2, while in the proposed ESS model, the ratio of the two probabilities varies exponentially depending on the relative gap between t and 3, although in both ESS models, the ratio of the two probabilities is ∆ when t is the minimum value (i.e., t = 3). Moreover, this study introduces a new decomposition theorem for the sum-symmetry model using the proposed ESS. The proposed decomposition theorem satisfies asymptotic equivalence for the test statistic.
序方列联表的相对指数和对称模型及和对称模型的正交分解
本文提出了一种新的指数和对称模型,适用于具有同列同行序分类的方形列联表。在现有的指数和对称(ESS)模型中,行水平小于列水平的行和列水平之和为t的概率比行水平大于列水平的行和列水平之和为t的概率高∆t−2倍。另一方面,在提出的ESS模型中,这两个概率的比值为∆t/3。也就是说,在现有ESS模型中,两种概率之比随t与2的绝对差距呈指数变化,而在本文提出的ESS模型中,两种概率之比随t与3的相对差距呈指数变化,尽管在两种ESS模型中,当t为最小值(即t = 3)时,两种概率之比均为∆。本文利用所提出的ESS引入了一个新的和对称模型分解定理。所提出的分解定理满足检验统计量的渐近等价。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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