Density-Dependent Growth and Production of Nile Tilapia (Oreochromis niloticus) Fingerlings Relative to Phytoplankton and Periphyton Biomass

Our Nature Pub Date : 2014-01-17 DOI:10.3126/ON.V11I2.9646
W. Jiwyam
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引用次数: 2

Abstract

The growth, production and survival of Nile tilapia Oreochromis niloticus , with an average individual weight of 0.2 g were used to determine the density-dependent growth and production relative to phytoplankton and periphyton biomass in periphyton-based aquaculture. The trial was conducted in 10 m 2 concrete tanks for a 56 day period. A 10 cm layer of soil was placed at the bottom of each tank. To act as substrates for periphyton, bamboo poles with an approximate submerged surface area of 50% to that of the total tank surface area were vertically posted in the tank bottom. A weekly fertilizer dose of urea and triple superphosphate at a rate of 28 kg N and 7 kg P/ha/week was added. Four stocking densities in triplicate were used: 5, 10, 20, and 40 fish/m 2 (50, 100, 200, and 400 fish/tank). The results indicated that the carrying capacity of periphyton-based tanks for Nile tilapia was 293 g/m 2 in a 56-day culture period. The relationships between gross yields of tilapia (y) and periphyton dry matter (x), or chlorophyll a (x) were described as y = 353.2483-109.1809x, R 2 = 0.5646, P = 0.005, y = 125.5916 + 0.9698x, R 2 = 0.5841, P = 0.004. Provision of substrates at 50% of total tank surface area was sufficient for periphyton production in nutrient-rich aquaculture ponds where grazing rate and fish density in the system are balanced. DOI: http://dx.doi.org/10.3126/on.v11i2.9646 Our Nature 2013, 11(2): 105-115
尼罗罗非鱼(Oreochromis niloticus)鱼种与浮游植物和周围植物生物量的密度依赖性生长和产量
以平均个体重0.2 g的尼罗罗非鱼(Oreochromis niloticus)的生长、产量和存活率为研究对象,研究了尼罗罗非鱼的密度依赖性生长和产量与浮游植物和周边植物生物量的关系。试验在10平方米的混凝土罐中进行,为期56天。在每个水箱底部放置一层10厘米的土壤。为了作为周边植物生长的基质,将淹没面积约为水箱总表面积50%的竹竿垂直放置在水箱底部。按氮28 kg /公顷/周、磷7 kg /公顷/周的速率施用尿素和三元过磷酸钙。4种放养密度分别为5、10、20和40鱼/ m2(50、100、200和400鱼/箱)。结果表明,在56 d的培养周期内,尼罗罗非鱼周生植物池的承载能力为293 g/ m2。罗非鱼总产量(y)与周围植物干物质(x)或叶绿素a (x)的关系为y = 353.2483 ~ 109.1809x, r2 = 0.5646, P = 0.005, y = 125.5916 + 0.9698x, r2 = 0.5841, P = 0.004。在营养丰富的水产养殖池塘中,在放牧率和鱼类密度平衡的情况下,提供占池总表面积50%的底物足以产生周生植物。DOI: http://dx.doi.org/10.3126/on.v11i2.9646 Our Nature, 2013, 11(2): 105-115
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