Pillai's problem with Padovan numbers and powers of two

Q4 Mathematics
Ana María García Lomeli, Santos Hernández Hernández
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引用次数: 7

Abstract

Let (Pn)n≥0 be the Padovan sequence given by P0 = 0, P1 = P2 = 1 and the recurrence formula Pn+3 = Pn+1 + Pn for all n ≥ 0. In this note we study and completely solve the Diophantine equation Pn - 2m = Pn1 - 2m1 in non-negative integers (n, m, n1, m1).
皮莱对帕多万数字和2的幂的问题
令(Pn)n≥0为P0 = 0, P1 = P2 = 1给出的Padovan序列,且对于所有n≥0,递归式Pn+3 = Pn+1 + Pn。本文研究并完全解非负整数(n, m, n1, m1)的丢芬图方程Pn - 2m = Pn1 - 2m1。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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来源期刊
Revista Colombiana de Matematicas
Revista Colombiana de Matematicas Mathematics-Mathematics (all)
CiteScore
0.60
自引率
0.00%
发文量
7
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