Topological algebras with subadditive boundedness radius

IF 0.5 Q3 MATHEMATICS
M. Sabet, R. Sanati
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引用次数: 0

Abstract

Let \(A\) be a topological algebra and \(\beta\) a subadditive boundedness radius on \(A\). In this paper we show that \(\beta\) is, under certain conditions, automatically submultiplicative. Then we apply this fact to prove that the spectrum of any element of \(A\) is non-empty. Finally, in the case when \(A\) is a normed algebra, we compare the initial normed topology with the normed topology \(\tau_{\beta}\), induced by \(\beta\) on \(A\), where \(\beta^{-1} (0)=0\).
具有次加性有界半径的拓扑代数
设\(A\)为拓扑代数,\(\beta\)为\(A\)上的次加性有界半径。本文证明了\(\beta\)在一定条件下是自动子乘法的。然后应用这一事实证明了\(A\)中任意元素的谱都是非空的。最后,在\(A\)是赋范代数的情况下,我们将初始赋范拓扑与由\(A\)上的\(\beta\)导出的赋范拓扑\(\tau_{\beta}\)进行比较,其中\(\beta^{-1} (0)=0\)。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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来源期刊
Cubo
Cubo Mathematics-Logic
CiteScore
1.20
自引率
0.00%
发文量
22
审稿时长
20 weeks
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