Disjoint Placement Probability of Line Segments via Geometry

Q4 Social Sciences
C. Ennis, J. Shier
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引用次数: 1

Abstract

Abstract We have shown that when any finite number n, of line segments with total combined length less than one, have their centers placed randomly inside the unit interval , the probability of obtaining a mutually disjoint placement of the segments within , is given by the expression where , and denotes the length of the k-th segment, Lk . The result is established by a careful analysis of the geometry of the event, “all segments disjoint and contained within [0,1],” considered as a subset of the uniform probability space of n centers, each of which is in ; that is to say, the unit n-cube of . This event has an interesting geometric structure consisting of disjoint, congruent, (up to a mirror image) polytopes within the unit n-cube. It is shown these event polytopes fit together perfectly to form, except for a set of measure zero, a partition of an n-dimensional cube with common edge length , and hence an n-volume given by the formula. In the case of n = 3 segments, the polytopes form one of the known tetrahedral partitions of the cube as discussed, for example in [4]. In fact for all n > 0, the polytopes comprise a partition of the n-dimensional hypercube, and are therefore n-dimensional space filling.
几何线段的不相交放置概率
摘要我们已经证明,当任意有限数量n个总组合长度小于1的线段的中心随机放置在单位区间内时,通过表达式给出了在单位区间中获得线段相互不相交放置的概率,其中,和表示第k个线段的长度Lk。该结果是通过仔细分析事件的几何结构而建立的,“所有不相交且包含在[0,1]内的分段”被认为是n个中心的一致概率空间的子集,每个中心都在;也就是说,的单位n立方体。这个事件有一个有趣的几何结构,由单位n立方体内的不相交、全等(直至镜像)多面体组成。结果表明,除了一组零测度外,这些事件多面体完美地结合在一起,形成了具有公共边长的n维立方体的分区,从而形成了由公式给出的n体积。在n的情况下 = 3段,多面体形成立方体的已知四面体分区之一,例如在[4]中所讨论的。事实上,所有n > 0,多面体包括n维超立方体的分区,因此是n维空间填充。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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来源期刊
College Mathematics Journal
College Mathematics Journal Social Sciences-Education
CiteScore
0.20
自引率
0.00%
发文量
52
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