A 4-choosable graph that is not (8:2)-choosable

Q2 Mathematics
Zdenvek Dvovr'ak, Xiaolan Hu, Jean-Sébastien Sereni
{"title":"A 4-choosable graph that is not (8:2)-choosable","authors":"Zdenvek Dvovr'ak, Xiaolan Hu, Jean-Sébastien Sereni","doi":"10.19086/aic.10811","DOIUrl":null,"url":null,"abstract":"List coloring is a generalization of graph coloring introduced by Erdős, Rubin and Taylor in 1980, which has become extensively studied in graph theory. A graph G is said to be k-choosable, or k-list-colorable, if, for every way of assigning a list (set) of k colors to each vertex of G, it is possible to choose a color from each list in such a way that no two neighboring vertices receive the same color. Note that if the lists are all the same, then this is asking for G to have chromatic number at most k.\n\nOne might think that the case where all the lists are the same would be the hardest: surely making the lists different should make it easier to ensure that neighboring vertices have different colors. Rather surprisingly, however, this is not the case. A counterexample is provided by the complete bipartite graph K2,4. If the two vertices in the first vertex class are assigned the lists {a,b} and {c,d}, while the vertices in the other vertex class are assigned the lists {a,c}, {a,d}, {b,c} and {b,d}, then it is easy to check that it is not possible to obtain a proper coloring from these lists, so G is not 2-choosable, and yet the chromatic number of G is 2. A famous theorem of Galvin, which solved the so-called Dinitz conjecture, states that the line graph of the complete bipartite graph Kn,n is n-choosable. Equivalently, if each square of an n×n grid is assigned a list of n colors, it is possible to choose a color from each list in such a way that no color appears more than once in any row or column.\n\nOne can generalize this notion by requiring a choice of not just one color from each list, but some larger number of colors. A graph G is said to be (A,B)-list-colorable if, for every assignment of lists to the vertices of G, each consisting of A colors, there is an assignment of sets of B colors to the vertices such that each vertex is assigned a set that is a subset of its list and the sets assigned to pairs of adjacent vertices are disjoint. (When B=1 this simply says that G is A-choosable.) In this short paper, the authors answer a question that has remained open for almost four decades since it was posed by Erdős, Rubin and Taylor in their seminal paper: if a graph is (A,B)-list-colorable, is it true that it is also (mA,mB)-list-colorable for every m≥1? Quite surprisingly, the answer is again negative - the authors construct a graph that is (4,1)-list-colorable but not (8,2)-list-colorable.","PeriodicalId":36338,"journal":{"name":"Advances in Combinatorics","volume":null,"pages":null},"PeriodicalIF":0.0000,"publicationDate":"2018-06-11","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"7","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"Advances in Combinatorics","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.19086/aic.10811","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"Q2","JCRName":"Mathematics","Score":null,"Total":0}
引用次数: 7

Abstract

List coloring is a generalization of graph coloring introduced by Erdős, Rubin and Taylor in 1980, which has become extensively studied in graph theory. A graph G is said to be k-choosable, or k-list-colorable, if, for every way of assigning a list (set) of k colors to each vertex of G, it is possible to choose a color from each list in such a way that no two neighboring vertices receive the same color. Note that if the lists are all the same, then this is asking for G to have chromatic number at most k. One might think that the case where all the lists are the same would be the hardest: surely making the lists different should make it easier to ensure that neighboring vertices have different colors. Rather surprisingly, however, this is not the case. A counterexample is provided by the complete bipartite graph K2,4. If the two vertices in the first vertex class are assigned the lists {a,b} and {c,d}, while the vertices in the other vertex class are assigned the lists {a,c}, {a,d}, {b,c} and {b,d}, then it is easy to check that it is not possible to obtain a proper coloring from these lists, so G is not 2-choosable, and yet the chromatic number of G is 2. A famous theorem of Galvin, which solved the so-called Dinitz conjecture, states that the line graph of the complete bipartite graph Kn,n is n-choosable. Equivalently, if each square of an n×n grid is assigned a list of n colors, it is possible to choose a color from each list in such a way that no color appears more than once in any row or column. One can generalize this notion by requiring a choice of not just one color from each list, but some larger number of colors. A graph G is said to be (A,B)-list-colorable if, for every assignment of lists to the vertices of G, each consisting of A colors, there is an assignment of sets of B colors to the vertices such that each vertex is assigned a set that is a subset of its list and the sets assigned to pairs of adjacent vertices are disjoint. (When B=1 this simply says that G is A-choosable.) In this short paper, the authors answer a question that has remained open for almost four decades since it was posed by Erdős, Rubin and Taylor in their seminal paper: if a graph is (A,B)-list-colorable, is it true that it is also (mA,mB)-list-colorable for every m≥1? Quite surprisingly, the answer is again negative - the authors construct a graph that is (4,1)-list-colorable but not (8,2)-list-colorable.
一个非(8:2)可选的4-可选图
表着色是由Erdős、Rubin和Taylor于1980年提出的图着色的一种推广,在图论中得到了广泛的研究。图G被称为k-可选择的,或者k-可着色的,如果,对于每一种分配k种颜色的列表(集合)到G的每个顶点的方法,它可能从每个列表中选择一种颜色,使得没有两个相邻的顶点接收到相同的颜色。注意,如果列表都是相同的,那么这就要求G的色数最多为k。有人可能会认为所有列表都相同的情况将是最难的:当然,使列表不同应该更容易确保相邻的顶点具有不同的颜色。然而,令人惊讶的是,事实并非如此。给出了完全二部图K2,4的反例。如果将第一个顶点类中的两个顶点赋值为列表{a,b}和{c,d},而另一个顶点类中的两个顶点赋值为列表{a,c}, {a,d}, {b,c}和{b,d},那么很容易检查出不可能从这些列表中获得适当的着色,因此G不是2-可选的,但G的色数为2。高尔文的一个著名定理,解决了所谓的迪尼茨猜想,指出完全二部图Kn,n的线形图是n可选的。同样地,如果为n×n网格的每个正方形分配了一个n种颜色的列表,则可以从每个列表中选择一种颜色,这样任何颜色在任何行或列中都不会出现超过一次。我们可以通过要求从每个列表中不仅选择一种颜色,而是选择更多的颜色来推广这个概念。图G是(A,B)-列表可着色的,如果对于G的每个顶点的列表分配,每个顶点由A种颜色组成,有B种颜色的集合分配给顶点,使得每个顶点被分配一个集合,该集合是其列表的子集,并且分配给相邻顶点对的集合是不相交的。(当B=1时,这仅仅说明G是可选的。)在这篇简短的论文中,作者回答了一个自Erdős、Rubin和Taylor在他们的开创性论文中提出以来一直悬而未决的问题:如果一个图是(a,B)-list-colorable,那么对于每一个m≥1,它是否也是(mA,mB)-list-colorable ?令人惊讶的是,答案还是否定的——作者构造了一个(4,1)-list-colorable而不是(8,2)-list-colorable的图。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
求助全文
约1分钟内获得全文 求助全文
来源期刊
Advances in Combinatorics
Advances in Combinatorics Mathematics-Discrete Mathematics and Combinatorics
CiteScore
3.10
自引率
0.00%
发文量
7
×
引用
GB/T 7714-2015
复制
MLA
复制
APA
复制
导出至
BibTeX EndNote RefMan NoteFirst NoteExpress
×
提示
您的信息不完整,为了账户安全,请先补充。
现在去补充
×
提示
您因"违规操作"
具体请查看互助需知
我知道了
×
提示
确定
请完成安全验证×
copy
已复制链接
快去分享给好友吧!
我知道了
右上角分享
点击右上角分享
0
联系我们:info@booksci.cn Book学术提供免费学术资源搜索服务,方便国内外学者检索中英文文献。致力于提供最便捷和优质的服务体验。 Copyright © 2023 布克学术 All rights reserved.
京ICP备2023020795号-1
ghs 京公网安备 11010802042870号
Book学术文献互助
Book学术文献互助群
群 号:481959085
Book学术官方微信