ANALYTICAL MODELLING BASED ON RESONANCE SCATTERING THEORY EXPLAINING THE NEEDLE VISIBILITY INCONSISTENCY IN B-MODE ULTRASOUND

IF 0.5 Q4 ENGINEERING, MULTIDISCIPLINARY
H. Susanti, S. Suprijanto, D. Kurniadi
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引用次数: 0

Abstract

In an ultrasound-guided needle insertion, physicians should adjust a certain insertion angle and the position of the transducer to ensure that the initial point and final target are in-plane inside the imaging plane. One of the crucial problems in this interventional procedure is poor and inconsistent needle visibility in B-mode ultrasound. In this research, some potential physical parameters, i.e., ultrasound frequency, the incident angle of the ultrasound beam, needle density, and dimension, are investigated through analytical modeling based on the resonance scattering model to understand their behavior in affecting needle visibility. 25G non-echogenic needle is used as a model object and assumed as stainless-steel hollow cylinder insonified by oblique incident plane wave varied within the frequency of 0–10 MHz and incident angle of 0°–45°. The results suggest that those physical parameters simultaneously affect the occurrence possibility of the resonant modes, which eventually affect the total scattering pressure field Ps in a non-linear way. These observed behaviors in the form of the spectrum map of resonance scattering pressure amplitude can be used to adapt a more beneficial combination of those physical parameters to obtain a higher possibility of good needle visibility through practical insertion application and potential echogenic technology or adaptive beamforming.
基于共振散射理论的分析模型解释B-模式超声中针头可见度的不一致性
在超声波引导的针头插入中,医生应调整一定的插入角度和换能器的位置,以确保初始点和最终目标位于成像平面内的平面内。这种介入手术的关键问题之一是B型超声中针的可见性差且不一致。在本研究中,通过基于共振散射模型的分析建模,研究了一些潜在的物理参数,即超声频率、超声束入射角、针头密度和尺寸,以了解它们在影响针头可见性方面的行为。以25G无回声针为模型对象,假设其为不锈钢空心圆柱体,由频率为0–10 MHz、入射角为0°–45°的倾斜入射平面波发出声波。结果表明,这些物理参数同时影响共振模式的发生可能性,共振模式最终以非线性方式影响总散射压力场Ps。这些以共振散射压力振幅的频谱图形式观察到的行为可以用于调整这些物理参数的更有益的组合,以通过实际的插入应用和潜在的回声技术或自适应波束形成来获得良好的针可见性的更高可能性。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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CiteScore
0.90
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