Irreducibility of Binomials

IF 0.5 Q3 MATHEMATICS
Haohao Wang, Jerzy Wojdylo, Peter Oman
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引用次数: 0

Abstract

In this paper, we prove that the family of binomials $x_1^{a_1} \cdots x_m^{a_m}-y_1^{b_1}\cdots y_n^{b_n}$ with $\gcd(a_1, \ldots, a_m, b_1, \ldots, b_n)=1$ is irreducible by identifying the connection between the irreducibility of a binomial in ${\mathbb C}[x_1, \ldots, x_m, y_1, \ldots, y_n]$ and ${\mathbb C}(x_2, \ldots, x_m, y_1, \ldots, y_n)[x_1]$. Then we show that the necessary and sufficient conditions for the irreducibility of this family of binomials is equivalent to the existence of a unimodular matrix $U_i$ with integer entries such that $(a_1, \ldots, a_m, b_1, \ldots, b_n)^T=U_i \be_i$ for $i\in \{1, \ldots, m+n\}$, where $\be_i$ is the standard basis vector.
二进制的不可约性
本文通过识别${\mathbb C}[x_2, \ldots, x_m, y_1, \ldots, b_n)=1$和${\mathbb C}(x_2, \ldots, x_m, y_1, \ldots, y_n]$中二项式的不可约性之间的联系,证明了$\gcd(a_1, \ldots, a_m, b_1, \ldots, y_n) $中的二项式族$x_1^{a_1} \cdots x_m^{a_1} -y_1 \cdots y_n)[x_1]$是不可约的。然后证明了该二项式族的不可约性的充分必要条件等价于具有整数项的一元矩阵$U_i$的存在性,使得$(a_1, \ldots, a_m, b_1, \ldots, b_n)^T=U_i \be_i$对于$i\in \{1, \ldots, m+n\}$,其中$\be_i$是标准基向量。
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来源期刊
CiteScore
0.90
自引率
16.70%
发文量
36
审稿时长
36 weeks
期刊介绍: The International Electronic Journal of Algebra is published twice a year. IEJA is reviewed by Mathematical Reviews, MathSciNet, Zentralblatt MATH, Current Mathematical Publications. IEJA seeks previously unpublished papers that contain: Module theory Ring theory Group theory Algebras Comodules Corings Coalgebras Representation theory Number theory.
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