Maximum Atom-Bond Sum-Connectivity Index of n-Order Trees With Fixed Number of Leaves

IF 1 Q1 MATHEMATICS
Sadia Noureen, Akbar Ali
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引用次数: 6

Abstract

Let G be a graph. For an edge e of G , denote by d e the number of edges adjacent to e . The atom-bond sum-connectivity (ABS) index of G is defined as ABS ( G ) = (cid:80) e ∈ E ( G ) (cid:112) 1 − 2( d e + 2) − 1 . A graph of order n is known as an n -order graph. The problem of determining trees possessing the minimum ABS index among all n -order trees with fixed number of leaves has recently been attacked in two preprints independently. This article provides a complete solution to the maximal version of the aforementioned problem
具有固定叶数的n阶树的最大原子键和连接性指数
设G是一个图。对于G的边e,用d e表示与e相邻的边的数量。G的原子键和连接性(ABS)指数定义为ABS(G)=(cid:80)e∈e(G)(cid:112)1−2(d e+2)−1。n阶图被称为n阶图。在所有具有固定叶数的n阶树中,确定具有最小ABS指数的树的问题最近在两份预印本中受到了独立的攻击。本文为上述问题的最大版本提供了一个完整的解决方案
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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来源期刊
Discrete Mathematics Letters
Discrete Mathematics Letters Mathematics-Discrete Mathematics and Combinatorics
CiteScore
1.50
自引率
12.50%
发文量
47
审稿时长
12 weeks
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