The Fundamental Theorem of Algebra via Real Polynomials

IF 0.4 4区 数学 Q4 MATHEMATICS
D. Daners, L. Paunescu
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引用次数: 0

Abstract

The fundamental theorem of algebra states that every polynomial p(z) over C of degree m ≥ 1 has a zero in C. There are many proofs of this theorem, but we have not found the elementary one presented here. Splitting the coefficients of p(z) into their real and imaginary parts,we find polynomials a(z) and b(z) with real coefficients such that p(z) = a(z) + ib(z). Then q(z) := p(z)p(z̄) = a(z)2 + b(z)2 is a polynomial of degree 2m ≥ 2 with real coefficients, and q(x) ≥ 0 for all x ∈ R. Moreover, q(z) = 0 if and only if p(z) = 0 or p(z̄) = 0. If q(z) = 0 for all z ∈ C, then F(z) := ∫ 1 0 z/q(tz) dt defines a primitive of 1/q(z) on C. Hence the integral over the piecewise smooth closed curve given by the interval [−r, r] and the positively oriented semi-cirlce Cr := {reiθ : θ ∈ [0, π ]} vanishes, that is, ∫ r −r 1 q(x) dx + ∫
通过实多项式的代数基本定理
代数基本定理表明,m≥1次的多项式p(z) / C在C中都有一个零。这个定理有很多证明,但我们还没有找到这里给出的初等证明。将p(z)的系数分解为实部和虚部,我们发现多项式a(z)和b(z)具有实数系数,使得p(z) = a(z) + ib(z)。则q(z):= p(z)p(z) = a(z)2 + b(z)2是一个2m阶≥2的实系数多项式,且对于所有x∈r, q(x)≥0,且当且仅当p(z) = 0或p(z) = 0时,q(z) = 0。如果对于所有z∈C q(z) = 0,则F(z):=∫10z /q(tz) dt在C上定义了一个1/q(z)的基元。因此由区间[- r, r]和正定向半圆Cr:= {reit θ: θ∈[0,π]}给出的分段光滑闭曲线上的积分,即∫r−r 1q (x) dx +∫
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来源期刊
American Mathematical Monthly
American Mathematical Monthly Mathematics-General Mathematics
CiteScore
0.80
自引率
20.00%
发文量
127
审稿时长
6-12 weeks
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