On perfect powers in $k$-generalized Pell sequence

IF 0.3 Q4 MATHEMATICS
Z. Şiar, R. Keskin, Elif Segah Öztas
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引用次数: 2

Abstract

. Let k > 2 and let ( P ( k ) n ) n > 2 − k be the k -generalized Pell sequence defined by P ( k ) n = 2 P ( k ) n − 1 + P ( k ) n − 2 + . . . + P ( k ) n − k for n > 2 with initial conditions In this study, we handle the equation P ( k ) n = y m in positive integers n , m , y , k such that k, y > 2 , and give an upper bound on n. Also, we will show that the equation P ( k ) n = y m with 2 6 y 6 1000 has only one solution given by P (2)7 = 13 2 .
k -广义Pell序列的完全幂
. 让k n > 2,让(P (k)) k n > 2−be the k -generalized佩尔奈德fi序列n: P (k) = 2 (k) n−1 P + P (k) n−2。。P (k) + n (n−k for > 2与初始条件在这个研究,我们把手the equation P (k) n = y在积极integers n, m、y y这样的那个k, k > 2,和给上束缚在一个n .也会,我们会show that the equation P (k) n = m和y = 2 6 y 1000唯一溶液赐予了:P(2) 7 = 13。
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来源期刊
Mathematica Bohemica
Mathematica Bohemica MATHEMATICS-
CiteScore
1.10
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0.00%
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审稿时长
52 weeks
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