Incorporating the sampling variation of the disease prevalence when calculating the sample size in a study to determine the diagnostic accuracy of a test

Qilong Yi , Tony Panzarella , Paul Corey
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引用次数: 10

Abstract

During the design stage of a study to assess the population sensitivity (PS) (or specificity) of a diagnostic test, the number of subjects (N) who will be administered both a gold standard test and a new test needs to be calculated. A common approach is to calculate the number of cases (n) with a specific disease or condition as diagnosed by the gold standard test first, and then to determine N based on the prevalence or incidence rate of the disease (PP) in the population, calculated as N=n/PP. Due to sampling variation, given the sample size N, the number of cases having the disease identified by the gold standard test could be less than N×PP. In this case, the study would be under-powered and may fail to produce an unbiased and precise estimate. In this study, we investigated this possibility for a situation where the required sample size is calculated using the confidence interval approach. When the sampling variation is considered, the variance of the sample sensitivity is slightly inflated, but its confidence interval width becomes widely dispersed. In order to reach the originally designed precision, adjustment in the sample size, N, is needed and suggested in this paper.

在计算一项研究的样本量时,纳入疾病流行率的抽样变化,以确定一项测试的诊断准确性
在评估诊断测试的群体敏感性(PS)(或特异性)的研究设计阶段,需要计算同时接受金标准测试和新测试的受试者人数(N)。一种常见的方法是先计算金标准试验诊断出的特定疾病或病症的病例数(n),然后根据该疾病在人群中的患病率或发病率(PP)确定n,计算公式为n =n/PP。由于抽样的变化,在给定样本量N的情况下,通过金标准测试确定的患病病例数可能少于N×PP。在这种情况下,研究将是动力不足的,可能无法产生一个公正和精确的估计。在本研究中,我们研究了使用置信区间方法计算所需样本量的情况下的这种可能性。当考虑抽样变化时,样本灵敏度的方差略有膨胀,但其置信区间宽度变得非常分散。为了达到最初设计的精度,需要对样本量N进行调整,本文也提出了相应的建议。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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