{"title":"Spaces of triangularizable matrices","authors":"Clément de Seguins Pazzis","doi":"10.1007/s44146-025-00190-w","DOIUrl":null,"url":null,"abstract":"<div><p>Let <span>\\(\\mathbb {F}\\)</span> be a field. We investigate the greatest possible dimension <span>\\(t_n(\\mathbb {F})\\)</span> for a vector space of <i>n</i>-by-<i>n</i> matrices with entries in <span>\\(\\mathbb {F}\\)</span> and in which every element is triangularizable over the ground field <span>\\(\\mathbb {F}\\)</span>. It is obvious that <span>\\(t_n(\\mathbb {F}) \\ge \\frac{n(n+1)}{2}\\)</span>, and we prove that equality holds if and only if <span>\\(\\mathbb {F}\\)</span> is not quadratically closed or <span>\\(n=1\\)</span>, excluding finite fields with characteristic 2. If <span>\\(\\mathbb {F}\\)</span> is infinite and not quadratically closed, we give an explicit description of the solutions with the critical dimension <span>\\(t_n(\\mathbb {F})\\)</span>, reducing the problem to the one of deciding for which integers <span>\\(k \\in \\mathopen {[\\![}2,n\\mathclose {]\\!]}\\)</span> all <i>k</i>-by-<i>k</i> symmetric matrices over <span>\\(\\mathbb {F}\\)</span> are triangularizable.</p></div>","PeriodicalId":46939,"journal":{"name":"ACTA SCIENTIARUM MATHEMATICARUM","volume":"91 3-4","pages":"369 - 399"},"PeriodicalIF":0.6000,"publicationDate":"2025-07-24","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"https://link.springer.com/content/pdf/10.1007/s44146-025-00190-w.pdf","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"ACTA SCIENTIARUM MATHEMATICARUM","FirstCategoryId":"1085","ListUrlMain":"https://link.springer.com/article/10.1007/s44146-025-00190-w","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"Q3","JCRName":"MATHEMATICS","Score":null,"Total":0}
引用次数: 0
Abstract
Let \(\mathbb {F}\) be a field. We investigate the greatest possible dimension \(t_n(\mathbb {F})\) for a vector space of n-by-n matrices with entries in \(\mathbb {F}\) and in which every element is triangularizable over the ground field \(\mathbb {F}\). It is obvious that \(t_n(\mathbb {F}) \ge \frac{n(n+1)}{2}\), and we prove that equality holds if and only if \(\mathbb {F}\) is not quadratically closed or \(n=1\), excluding finite fields with characteristic 2. If \(\mathbb {F}\) is infinite and not quadratically closed, we give an explicit description of the solutions with the critical dimension \(t_n(\mathbb {F})\), reducing the problem to the one of deciding for which integers \(k \in \mathopen {[\![}2,n\mathclose {]\!]}\) all k-by-k symmetric matrices over \(\mathbb {F}\) are triangularizable.