Di-μ-hydroxido-bis[iodidodiphenyltin(IV)]–1,3-dimethylimidazolidin-2-one (1/2)

IUCrData Pub Date : 2025-08-01 DOI:10.1107/S2414314625007114

Hans Reuter

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Abstract

In the solid, state diphenyltin(IV)-hydroxide-iodide-N,N′-dimethylpropylene-urea, Ph₂Sn(OH) ·DMPU, consists of centrosymmetric dimers exhibiting the characteristic structural features of diorganotin(IV)-hydroxide-halides.

The title compound, di-μ-hydroxido-bis[iodidodiphenyltin(IV)]–1,3-dimethylimidazolidin-2-one (1/2), [Sn(C₆H₅)₂I(OH)]·2C₆H₁₂N₂O, represents only the second example in the dimeric diorganotin(IV)-hydroxide-halide solvates [R₂Sn(OH)Hal]₂·2BB with Hal = I. As is usual for this class of compound, dimerization takes place via the oxygen atoms of the hydroxyl groups and leads to a planar, centrosymmetric, four-membered Sn—O ring of rhomboidal shape whose Sn—O distances [2.024 (2)/2.174 (2) Å] are determined by the position (axial or equatorial) of the oxygen atom on the respective trigonal–pyramidal coordinated tin atom while the bond angles are acute [70.74 (8)°] at the tin atoms and obtuse [109.26 (8)°] at the oxygen atoms.

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Di -μ-hydroxido-bis - [iodido-diphenyl-tin (IV)] 1, 3-di-methyl-imidazolidin-2-one(1/2)。

二μ-羟基-双-[碘二苯基锡（IV）]-1,3-二甲基-咪唑烷-2- 1 (1/2),[Sn(C6H5)2I(OH)]·2C6H12N2O，是二聚体二有机锡(IV)-羟基卤化物溶剂化物[R 2Sn(OH)Hal]2·2BB （Hal = 1）中的第二个例子。对于这类化合物，通常通过羟基上的氧原子发生二聚，形成平面的中心对称结构。四元菱形Sn-O环，其Sn-O距离[2.024 (2)/2.174 (2)Å]由氧原子在各自三角-锥体配位锡原子上的位置（轴向或赤道）决定，键角在锡原子处为锐角[70.74(8)°]，在氧原子处为钝角[109.26(8)°]。

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