N-(4-Methoxy-2-methyl-5-nitrophenyl)acetamide

IUCrData Pub Date : 2025-06-01 DOI:10.1107/S2414314625004705

Rao M. Uppu , Frank R. Fronczek

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引用次数: 0

Abstract

In the title compound, C₁₀H₁₂N₂O₄, the four substituents lie out of the phenyl plane by varying degrees. In the extended structure, the acetamide NH group donates a hydrogen bond to an acetamide carbonyl O atom, thereby forming chains propagating in the [010] direction.

In the title compound, C₁₀H₁₂N₂O₄, the four substituents lie out of the phenyl plane by varying degrees. The methyl C atom lies 0.019 (3) Å out of plane, while the methoxy O and C atoms lie 0.067 (2) and 0.042 (3) Å out of plane, respectively, with the C—C—O—C torsion angle being 3.3 (2)°. The plane of the nitro group is twisted out of the phenyl plane, forming a dihedral angle of 12.03 (9)° with it. The acetamide substituent is twisted considerably more out of the phenyl plane, forming a dihedral angle of 47.24 (6)° with it. In the extended structure, the acetamide NH group donates a hydrogen bond to an acetamide carbonyl O atom, thereby forming chains propagating in the [010] direction.

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N - (4-Meth-oxy-2-methyl-5-nitro-phen-yl)乙酰胺。

在标题化合物C10H12N2O4中，四个取代基不同程度地位于苯基平面外。甲基C原子在平面外0.019 (3)Å，甲基氧和C原子分别在平面外0.067(2)和0.042 (3)Å， C-C-O-C的扭转角为3.3(2)°。硝基平面扭出苯基平面，与苯基形成12.03(9)°的二面角。乙酰胺取代基在苯基平面外扭得更大，与苯基形成47.24(6)°的二面角。在扩展结构中，乙酰胺NH基团向乙酰胺羰基O原子提供氢键，从而形成沿[010]方向传播的链。

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