{"title":"<i>N</i>-(4-Meth-oxy-2-methyl-5-nitro-phen-yl)acetamide.","authors":"Rao M Uppu, Frank R Fronczek","doi":"10.1107/S2414314625004705","DOIUrl":null,"url":null,"abstract":"<p><p>In the title compound, C<sub>10</sub>H<sub>12</sub>N<sub>2</sub>O<sub>4</sub>, the four substituents lie out of the phenyl plane by varying degrees. The methyl C atom lies 0.019 (3) Å out of plane, while the meth-oxy O and C atoms lie 0.067 (2) and 0.042 (3) Å out of plane, respectively, with the C-C-O-C torsion angle being 3.3 (2)°. The plane of the nitro group is twisted out of the phenyl plane, forming a dihedral angle of 12.03 (9)° with it. The acetamide substituent is twisted considerably more out of the phenyl plane, forming a dihedral angle of 47.24 (6)° with it. In the extended structure, the acetamide NH group donates a hydrogen bond to an acetamide carbonyl O atom, thereby forming chains propagating in the [010] direction.</p>","PeriodicalId":94324,"journal":{"name":"IUCrData","volume":"10 Pt 6","pages":"x250470"},"PeriodicalIF":0.0000,"publicationDate":"2025-06-03","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"https://www.ncbi.nlm.nih.gov/pmc/articles/PMC12230592/pdf/","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"IUCrData","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1107/S2414314625004705","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"2025/6/1 0:00:00","PubModel":"eCollection","JCR":"","JCRName":"","Score":null,"Total":0}
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Abstract
In the title compound, C10H12N2O4, the four substituents lie out of the phenyl plane by varying degrees. The methyl C atom lies 0.019 (3) Å out of plane, while the meth-oxy O and C atoms lie 0.067 (2) and 0.042 (3) Å out of plane, respectively, with the C-C-O-C torsion angle being 3.3 (2)°. The plane of the nitro group is twisted out of the phenyl plane, forming a dihedral angle of 12.03 (9)° with it. The acetamide substituent is twisted considerably more out of the phenyl plane, forming a dihedral angle of 47.24 (6)° with it. In the extended structure, the acetamide NH group donates a hydrogen bond to an acetamide carbonyl O atom, thereby forming chains propagating in the [010] direction.
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