Computational study on Pd-catalyzed ipso,meta-dimethylation of ortho-substituted iodoarenes: mechanisms and the role of the base†

Kang Lv , Yihang Zhou , Zitong Meng , Jing Zhang , Tao Liu
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Abstract

Density functional theory (DFT) calculations were performed to study Pd-catalyzed ipso,meta-dimethylation reactions of ortho-substituted iodoarenes. In the presence of K2CO3, aryl-I oxidative addition on Pd(0) catalysts can generate an arylpalladium(ii) intermediate, which undergoes two sequential processes of C–H activation, CH3–I oxidative addition (Ar–C reductive elimination/CH3–I oxidative addition/Ar–C oxidative addition), and Ar–C reductive elimination to generate a dimethylated intermediate. Then hydrogen transfer, C-hydride reductive elimination, and ligand exchange can take place to generate 2,6-dimethylanisole . With KOAc as the base, 2,3-dihydrobenzofuran can be obtained via aryl-I oxidative addition, two sequential processes of C–H activation/Ar–C reductive elimination/CH3–I oxidative addition/Ar–C oxidative addition/Ar–C reductive elimination, the third C–H activation, reductive elimination, and ligand exchange, respectively. The competition between the third C–H activation and the hydrogen transfer from the dimethylated intermediate determines the selectivity of the reaction. The hydrogen transfer is generally superior to the third C–H activation due to the stronger reactivity of the methyl group in methanol than a normal methyl group. When K2CO3 is used, such an electronic effect is dominant. However, when KOAc is employed, its different structure and properties compared to K2CO3 make the ligand exchange step highly endergonic, thereby rendering subsequent hydrogen transfer unfavorable and leading to 2,3-dihydrobenzofuran as the final product.

Abstract Image

邻位取代碘芳烃pd催化异位二甲基化的计算研究:机理及碱的作用
采用密度泛函理论(DFT)计算了邻取代碘芳烃在pd催化下的异位二甲基化反应。在K2CO3存在下,Pd(0)催化剂上芳基- I氧化加成生成芳基钯(II)中间体,经过C−H活化、CH3−I氧化加成(Ar−C还原加成/CH3−I氧化加成/Ar−C氧化加成)和Ar−C还原加成生成二甲基化中间体。然后进行氢转移、C -氢化物还原消除和配体交换,生成2,6-二甲基甲磺酸3b。以KOAc为碱,通过芳基- I氧化加成、C−H活化/Ar−C还原消除/CH3−I氧化加成/Ar−C氧化加成/Ar−C还原消除、第三次C−H活化、还原消除和配体交换得到2,3-二氢苯并呋喃4b。第三次C−H活化和二甲基化中间体的氢转移之间的竞争决定了反应的选择性。由于甲基在甲醇中的反应性比普通甲基强,因此氢转移通常优于第三次C−H活化。当使用K2CO3时,这种电子效应占主导地位。然而,当使用KOAc时,由于与K2CO3的结构和性质不同,导致配体交换步骤高度自吸,从而导致后续的氢转移不利,最终产物为2,3-二氢苯并呋喃4b。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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CiteScore
7.80
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