{"title":"Almost regular subgraphs under spectral radius constrains","authors":"Weilun Xu, Guorong Gao, An Chang","doi":"arxiv-2409.10853","DOIUrl":null,"url":null,"abstract":"A graph is called $K$-almost regular if its maximum degree is at most $K$\ntimes the minimum degree. Erd\\H{o}s and Simonovits showed that for a constant\n$0< \\varepsilon< 1$ and a sufficiently large integer $n$, any $n$-vertex graph\nwith more than $n^{1+\\varepsilon}$ edges has a $K$-almost regular subgraph with\n$n'\\geq n^{\\varepsilon\\frac{1-\\varepsilon}{1+\\varepsilon}}$ vertices and at\nleast $\\frac{2}{5}n'^{1+\\varepsilon}$ edges. An interesting and natural problem\nis whether there exits the spectral counterpart to Erd\\H{o}s and Simonovits's\nresult. In this paper, we will completely settle this issue. More precisely, we\nverify that for constants $\\frac{1}{2}<\\varepsilon\\leq 1$ and $c>0$, if the\nspectral radius of an $n$-vertex graph $G$ is at least $cn^{\\varepsilon}$, then\n$G$ has a $K$-almost regular subgraph of order $n'\\geq\nn^{\\frac{2\\varepsilon^2-\\varepsilon}{24}}$ with at least $\nc'n'^{1+\\varepsilon}$ edges, where $c'$ and $K$ are constants depending on $c$\nand $\\varepsilon$. Moreover, for $0<\\varepsilon\\leq\\frac{1}{2}$, there exist\n$n$-vertex graphs with spectral radius at least $cn^{\\varepsilon}$ that do not\ncontain such an almost regular subgraph. Our result has a wide range of\napplications in spectral Tur\\'{a}n-type problems. Specifically, let\n$ex(n,\\mathcal{H})$ and $spex(n,\\mathcal{H})$ denote, respectively, the maximum\nnumber of edges and the maximum spectral radius among all $n$-vertex\n$\\mathcal{H}$-free graphs. We show that for $1\\geq\\xi > \\frac{1}{2}$,\n$ex(n,\\mathcal{H}) = O(n^{1+\\xi})$ if and only if $spex(n,\\mathcal{H}) =\nO(n^\\xi)$.","PeriodicalId":501407,"journal":{"name":"arXiv - MATH - Combinatorics","volume":"39 1","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2024-09-17","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv - MATH - Combinatorics","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/arxiv-2409.10853","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
Abstract
A graph is called $K$-almost regular if its maximum degree is at most $K$
times the minimum degree. Erd\H{o}s and Simonovits showed that for a constant
$0< \varepsilon< 1$ and a sufficiently large integer $n$, any $n$-vertex graph
with more than $n^{1+\varepsilon}$ edges has a $K$-almost regular subgraph with
$n'\geq n^{\varepsilon\frac{1-\varepsilon}{1+\varepsilon}}$ vertices and at
least $\frac{2}{5}n'^{1+\varepsilon}$ edges. An interesting and natural problem
is whether there exits the spectral counterpart to Erd\H{o}s and Simonovits's
result. In this paper, we will completely settle this issue. More precisely, we
verify that for constants $\frac{1}{2}<\varepsilon\leq 1$ and $c>0$, if the
spectral radius of an $n$-vertex graph $G$ is at least $cn^{\varepsilon}$, then
$G$ has a $K$-almost regular subgraph of order $n'\geq
n^{\frac{2\varepsilon^2-\varepsilon}{24}}$ with at least $
c'n'^{1+\varepsilon}$ edges, where $c'$ and $K$ are constants depending on $c$
and $\varepsilon$. Moreover, for $0<\varepsilon\leq\frac{1}{2}$, there exist
$n$-vertex graphs with spectral radius at least $cn^{\varepsilon}$ that do not
contain such an almost regular subgraph. Our result has a wide range of
applications in spectral Tur\'{a}n-type problems. Specifically, let
$ex(n,\mathcal{H})$ and $spex(n,\mathcal{H})$ denote, respectively, the maximum
number of edges and the maximum spectral radius among all $n$-vertex
$\mathcal{H}$-free graphs. We show that for $1\geq\xi > \frac{1}{2}$,
$ex(n,\mathcal{H}) = O(n^{1+\xi})$ if and only if $spex(n,\mathcal{H}) =
O(n^\xi)$.