ON A PROBLEM OF PONGSRIIAM ON THE SUM OF DIVISORS

IF 0.6 4区 数学 Q3 MATHEMATICS
RUI-JING WANG
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引用次数: 0

Abstract

For any positive integer n, let Abstract Image$\sigma (n)$ be the sum of all positive divisors of n. We prove that for every integer k with Abstract Image$1\leq k\leq 29$ and Abstract Image$(k,30)=1,$ Abstract Image$$ \begin{align*} \sum_{n\leq K}\sigma(30n)>\sum_{n\leq K}\sigma(30n+k) \end{align*} $$

for all Abstract Image$K\in \mathbb {N},$ which gives a positive answer to a problem posed by Pongsriiam [‘Sums of divisors on arithmetic progressions’, Period. Math. Hungar. 88 (2024), 443–460].

关于除数之和的庞氏难题
对于任意正整数 n,让 $\sigma (n)$ 是 n 的所有正除数之和。我们证明,对于每一个整数k,只要有$1\leq k\leq 29$和$(k,30)=1,$$ \begin{align*}。\sum_{n\leq K}\sigma(30n)>\sum_{n\leq K}\sigma(30n+k) \end{align*}$$for all $K\in \mathbb {N}, $ 这给了 Pongsriiam 提出的问题一个肯定的答案['Sums of divisors on arithmetic progressions', Period.Math.匈牙利。88 (2024), 443-460].
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来源期刊
CiteScore
1.20
自引率
14.30%
发文量
149
审稿时长
4-8 weeks
期刊介绍: Bulletin of the Australian Mathematical Society aims at quick publication of original research in all branches of mathematics. Papers are accepted only after peer review but editorial decisions on acceptance or otherwise are taken quickly, normally within a month of receipt of the paper. The Bulletin concentrates on presenting new and interesting results in a clear and attractive way. Published Bi-monthly Published for the Australian Mathematical Society
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