Undecidability of Translational Tiling of the 4-dimensional Space with a Set of 4 Polyhypercubes

Chao Yang, Zhujun Zhang
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Abstract

Recently, Greenfeld and Tao disproof the conjecture that translational tilings of a single tile can always be periodic [Ann. Math. 200(2024), 301-363]. In another paper [to appear in J. Eur. Math. Soc.], they also show that if the dimension $n$ is part of the input, the translational tiling for subsets of $\mathbb{Z}^n$ with one tile is undecidable. These two results are very strong pieces of evidence for the conjecture that translational tiling of $\mathbb{Z}^n$ with a monotile is undecidable, for some fixed $n$. This paper shows that translational tiling of the $3$-dimensional space with a set of $5$ polycubes is undecidable. By introducing a technique that lifts a set of polycubes and its tiling from $3$-dimensional space to $4$-dimensional space, we manage to show that translational tiling of the $4$-dimensional space with a set of $4$ tiles is undecidable. This is a step towards the attempt to settle the conjecture of the undecidability of translational tiling of the $n$-dimensional space with a monotile, for some fixed $n$.
用一组 4 个多立方体平移平铺 4 维空间的不可判定性
最近,格林菲尔德和陶推翻了单块瓦的平移平铺总是周期性的猜想[Ann. Math. 200(2024),301-363].在另一篇论文[将发表于《欧洲数学学会杂志》]中,他们还证明了如果维数 $n$ 是输入的一部分,那么只有一块瓦的 $\mathbb{Z}^n$ 子集的平移平铺是不可判定的。这两个结果非常有力地证明了这样一个猜想,即对于某个固定的 $n$,具有单瓦片的 $mathbb{Z}^n$ 的平移平铺是不可判定的。本文证明了用一组 5$ 多面体平移平铺 3$ 维空间是不可判定的。通过引入一种将一组多立方体及其平铺从 3 美元维空间提升到 4 美元维空间的技术,我们设法证明了用一组 4 美元的平铺平移 4 美元维空间是不可判定的。这是朝着尝试解决在某个固定的 $n$ 条件下,用一个单瓷砖对 $n$ 维空间进行平移平铺的不可判定性猜想迈出的一步。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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