Feather keratin in Pavo cristatus: A tentative structure

Peter Russ, Helmut O K Kirchner, Herwig Peterlik, Ingrid M Weiss
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引用次数: 0

Abstract

The filament of the F-keratin polymer is an alternating arrangement of two tetrameric sequence segments, the "N-block" made of four strands AA 1—52, a twisted parallelepiped and the "C-block", a sandwich of four strands AA 81—100. The N-blocks have 89° internal rotation within eight levels of β-sandwiches strengthened by three disulfide bonds per monomer. The C-blocks contain 5 aromatic residues, they provide resilience, like vertebral discs in a spinal column. The pitch of an N+C-block octamer is 10 nm. Solidification of F-keratin may involve the "C-blocks" to temporarily mold into "C-wedges" of 18° tilt, which align the polymer filaments into laterally amorphous fiber-reinforced composites of 9.5 nm axial periodicity. This distance corresponds to the length of the fully stretched AA 53—80 matrix segment. The "spinal column" is deformed like in scoliosis and unwinds under compression when F-keratin filaments perfectly align horizontally and form stacked sheets in the solid state.
Pavo cristatus 的羽毛角蛋白:暂定结构
F 角蛋白聚合物的丝是由两个四聚体序列段交替排列而成的,"N 块 "由四股 AA 1-52 组成,是一个扭曲的平行四边形,而 "C 块 "则是由四股 AA 81-100 组成的夹心层。N 嵌段在八个层级的β-三明治内有 89°的内部旋转,每个单体由三个二硫键加固。C 嵌段包含 5 个芳香族残基,它们具有弹性,就像脊柱中的椎间盘。N+C 块八聚体的间距为 10 纳米。F-角蛋白凝固时,"C-块 "可能会暂时模塑成倾斜度为 18°的 "C-脊",从而将聚合物丝排列成轴向周期为 9.5 纳米的横向无定形纤维增强复合材料。这个距离相当于完全拉伸的 AA 53-80 基质段的长度。当 F 角蛋白丝完全水平排列并在固态下形成叠片时,"脊柱 "就会像脊柱侧弯一样变形,并在压缩下松开。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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