Global existence and boundedness in a chemotaxis model with singular sensitivity and nonlocal term

Wenping Du, Suying Liu, Wenji Zhang
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Abstract

The chemotaxis system

$$\begin{aligned} \left\{ \begin{aligned}&u_t=\Delta u-\chi \nabla \cdot \left( \frac{u}{v}\nabla v\right) + u^{\alpha }\left( \gamma -\mu \int \limits _{\Omega }u^{\beta }\right) ,{} & {} x\in \Omega ,t>0,\\&v_t=\epsilon \Delta v-v+u,{} & {} x\in \Omega ,t>0, \end{aligned}\right. \end{aligned}$$

is considered under homogeneous Neumann boundary conditions in smoothly bounded domain \(\Omega \subseteq \mathbb {R}^n\), \(n\ge 2\), with constants \(0<\epsilon <1\), \(0<\chi <1-\epsilon \). It is asserted that the problem possesses a uniquely global classical solution whenever the numbers \(\alpha , \beta \) satisfy \(1<\alpha <2\), \(\beta >\frac{n}{2}+\alpha -1\) or \(\alpha \ge 2\), \(\beta >\frac{n}{2}(\alpha -1)+1\). Moreover, it is shown that if \(1<\alpha <2\), \(\beta >\max \{\frac{n}{2}+\alpha -1, \frac{(\alpha -1)(1-\epsilon )}{(2-\alpha )\chi }+1\}\) and \(\gamma >0\) is sufficiently large, then the global-in-time solution is uniformly bounded. In addition, we get similar results for the case of \(n=1\), which is worth mentioning that the requirement for \(\epsilon \) and \(\chi \) is very weak in the global existence result.

具有奇异敏感性和非局部项的趋化模型中的全局存在性和有界性
趋化系统\u=Delta u-\chi \nabla \cdot \left( \frac{u}{v}\nabla v\right) + u^{\alpha }\left( \gamma -\mu \int \limits _\Omega }u^{\beta }\right) ,{} &;{} x\in \Omega ,t>0,\&v_t=\epsilon \Delta v-v+u,{} & {} x\in \Omega ,t>0,\end{aligned}\right.\在平滑有界域 \(\Omega \subseteq \mathbb {R}^n\), \(n\ge 2\), 带常数 \(0<\epsilon <1\), \(0<\chi <1-\epsilon \)的同质诺依曼边界条件下考虑这个问题。有人断言,只要数 \(\alpha , \beta \) 满足 \(1<\alpha <2\), \(\beta >\frac{n}{2}+\alpha -1\) 或 \(\alpha \ge 2\), \(\beta >\frac{n}{2}(\alpha -1)+1\), 问题就有一个唯一的全局经典解。此外,研究表明,如果 \(1<\alpha <2\),\(\beta >\max \{\frac{n}{2}+\alpha -1, \frac{(\alpha -1)(1-\epsilon )}{(2-\alpha )\chi }+1\}\) 和\(\gamma >0\) 足够大,那么全局时间解是均匀有界的。此外,我们对 \(n=1\) 的情况也得到了类似的结果,值得一提的是,在全局存在性结果中,对 \(\epsilon \) 和 \(\chi \) 的要求非常弱。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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